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Novosadov [1.4K]
4 years ago
6

the perimeter of a square clock is 16 wholes and 6/9 inches.The perimeter of a rectangular clock is 16 wholes and 16/18 inches.W

rite an inequality comparing the two perimeters. PLEASE HELP ME
Mathematics
1 answer:
sergejj [24]4 years ago
4 0
6/9 and 16/18 is what we will mainly look at since the whole numbers are the same. the common denominator is 18. so you would multiply 6/9 by 2 (both the numerator and denominator multiplied by 2 ) therefore you will get 12/18. Which is bigger 12/18 or 16/18? 16/18 is bigger, therefore you would say sixteen and 6/9 is less than sixteen and 16/18. your answer should be this below. :)
16,6/9 < 16, 16/18.
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Evaluate:<br> <img src="https://tex.z-dn.net/?f=32%5E%7B-%20%5Cfrac%7B2%7D%7B5%7D%20%7D%20%3Cbr%3E%3Cbr%3E%3Cbr%3E%3Cbr%3E%3Cbr%
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32^{- \frac{2}{5} }  =  ( \frac{1}{32}) ^{ \frac{2}{5} } = ( \frac{1}{32} )^{ \frac{1}{5} *2}  =  [ ( \frac{1}{32}) ^{ \frac{1}{5} } ]^{2}  =  ( \sqrt[5]{ \frac{1}{32} } ) ^{2}  =  ( \sqrt[5]{ \frac{1}{2}*  \frac{1}{2} *  \frac{1}{2} *  \frac{1}{2} *  \frac{1}{2}   } )^{2} = ( \frac{1}{2} )^{2}   answer 

<span>the notebook
</span>(32)^{-  \frac{2}{5} }  =  ( \sqrt[5]{ \frac{1}{32} } )^{2}  = ( \frac{1}{2}  )^{2} =  \frac{1}{4}<span>

</span>
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