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Firdavs [7]
3 years ago
6

What is the measure of one interior angle of a polygon that has 50 sides

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

Answer: 172.8°

Step-by-step explanation:

For a regular polynomial of N sides, the sum of all interior angles must be equal to:

Sum = (N - 2)*180°.

In this case we have N = 50

Then:

Sum = (50 - 2)*180° = 48*180°

Now, if all the 50 interior angles have the same measure, then the measure of each one will be equal to the quotient between the sum and the number of sides, this is:

Sum/50 = (48/50)*180° = 172.8°

Then the interior angles of a regular polygon of 50 sides is 172.8°

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Answer is C sir......
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3 years ago
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A man (M) is standing on the bank of a river that is 0.9 miles wide. He wants to reach a house (B) on the opposite shore that is
atroni [7]

Answer:

The distance between the hose and the point (P) is 0.9 miles

Step-by-step explanation:

Here we have

Speed of rowing the boat = 3 mph

Speed of waling = 4.5 mph

Since the speed of walking is more than that of to row the  boat, the location of where he should dock his boat in order to minimize the total time he would need to reach the house is the shortest distance across the river to the house

Therefore the location of the point (P) should be directly opposite the house across the water and the distance id 0.9 miles.

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3 years ago
The asymptote function f(x)=3^x+4 is y=
swat32

The asymptote of the function f(x)=3^x is y = 0.

The asymptote of the function f(x)=3^x+4 is y = 0+4=4

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7 0
3 years ago
Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche
allochka39001 [22]

Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

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3 years ago
What is the factored form of 8x²-36x-20?
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Answer:

(4x + 2)( 2x - 10)

Step-by-step explanation:

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