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3 years ago

What is the measure of one interior angle of a polygon that has 50 sides

Mathematics

1 answer:

pashok25 [27]3 years ago

3 0

Answer: 172.8°

Step-by-step explanation:

For a regular polynomial of N sides, the sum of all interior angles must be equal to:

Sum = (N - 2)*180°.

In this case we have N = 50

Then:

Sum = (50 - 2)*180° = 48*180°

Now, if all the 50 interior angles have the same measure, then the measure of each one will be equal to the quotient between the sum and the number of sides, this is:

Sum/50 = (48/50)*180° = 172.8°

Then the interior angles of a regular polygon of 50 sides is 172.8°

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If angle 4 is 52.7, what are the measures of angles 1,2, and 3?

shusha [124]

Answer:

127.3
52.7
127.3
52.7

Step-by-step explanation:

Since we know the angle measure of angle 4, we already know that angle 2 will have the same measure according to do the vertical angle theorem. Now to find angles 1 and 3, we can make an equation and solve for x (supplementary angles).

52.7 + x = 180

x = 127.3

Best of Luck!

6 0

2 years ago

Which is the graph inequality x-2y_>-12

Zigmanuir [339]

Answer:

The graph for x-2y>=-12 needs to get y aloneso add 2y to both sides to getx >=-12 +2ythen add 12 to both sides of the in equalityx+12 >=2ynext divide each term by 2x/2 + 6 >= yy<= x/2 + 6so the graph connects (0,6) and (2,7) and shade below the solid line

5 0

3 years ago

A martial artist is practicing breaking 5 boards. He is able to break a board with probability 0.8. (a) What is the probability

konstantin123 [22]

Answer:

(a) = 0.32 or 8/25

(b) = 0.48 or 12/25

Step-by-step explanation:

(a):

0.8 x 2/5

8/10 x 4/10

(8 x 4) / (10 x 10)

(32) / (100)

0.32 or 8/25

(b):

0.8 x 3/5

8/10 x 6/10

(8 x 6) / (10 x 10)

(48) / (100)

0.48 or 12/25

(c):

0.8 x 5

8/10 x 50/10

(8 x 50) / (10 x 10)

(400) / (100)

4 Boards

4 0

3 years ago

What is 3½ tons =___pounds?

artcher [175]

Answer:

7,000 LBs

Step-by-step explanation:

1 ton is 2,000, half of a ton is 1,000

5 0

2 years ago

Read 2 more answers

Determine whether the relation R on the set of all Web pages is reflexive, symmetric, antisymmetric, and/or transitive, where (a

xxMikexx [17]

Answer:

a) R is reflexive, R is not symmetric, R is not anti-symmetric, R is transitive.

b) R is reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

c) R is not reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

Step-by-step explanation:

(a, b) ∈ R if and only if everyone who has visited Web page a has also visited Web page b.

Obviously R is reflexive (aRa)

Everyone who has visited Web page a has also visited Web page a

R is not symmetric (aRb does not imply bRa)

If everyone who has visited Web page a has also visited Web page b does not mean that everyone who has visited Web page b has also visited Web page a

R is not anti-symmetric (aRb and bRa does not imply a=b)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page a does not mean the web pages are the same.

R is transitive (aRb and bRc implies aRc)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page c implies that everyone who has visited Web page a has also visited Web page c.

(a, b) ∈ R if and only if there are no common links found on both Web page a and Web page b.

R is obviously reflexive (aRa)

R is symmetric (aRb implies bRa)

if there are no common links found on both Web page a and Web page b, then there are no common links found on both Web page b and Web page a.

R is not anti-symmetric (aRb and bRa does not imply a=b)

if there are no common links found on both Web page a and Web page b and there are no common links found on both Web page b and Web page a does not mean a and b are the same web page.

R is not transitive (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a and c have a common link and b has no external links at all.

Then obviously (a,b)∈R and (b,c)∈R since b has no links, but (a,c)∉R because they have a common link.

(a, b) ∈ R if and only if there is at least one common link on Web page a and Web page b

R is not reflexive

If the web page a does not have any link at all, then a is not related to a.

R is symmetric (aRb implies bRa)

if there is at least one common link found on Web page a and Web page b, then there is at least one common link found on Web page b and Web page a.

R is not anti-symmetric (aRb and bRa does not imply a=b)

if there is at least one common link found on Web page a and Web page b and there is at least one common link found on Web page b and Web page a does not mean the web pages are the same

R is not transitive (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a has only two links L1 and L2, b has only two links L2 and L3 c has only two links L3 and L4.

Then (a, b) ∈ R since a and b have the common link L2, (b, c) ∈ R for b and c have the common link L3, but a and c have no common links, therefore (a,c)∉R

5 0

3 years ago