Question

What is the measure of one interior angle of a polygon that has 50 sides

Answer 1

Answer: 172.8°

Step-by-step explanation:

For a regular polynomial of N sides, the sum of all interior angles must be equal to:

Sum = (N - 2)*180°.

In this case we have N = 50

Then:

Sum = (50 - 2)*180° = 48*180°

Now, if all the 50 interior angles have the same measure, then the measure of each one will be equal to the quotient between the sum and the number of sides, this is:

Sum/50 = (48/50)*180° = 172.8°

Then the interior angles of a regular polygon of 50 sides is 172.8°