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matrenka [14]
3 years ago
12

Help pls... friend needs and and dose not have brainly lol

Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Answer:

8) Number of terms : Monomial

Degree : Constant polynomial

9) Not a polynomial

Step-by-step explanation:

8) Recall that a polynomial with one term is a monomial

A polynomial with a degree of zero is a constant polynomial

Therefore 1 is a monomial, when we classify by number of terms and it is a constant polynomial when we classify by degree since the degree is zero.

9) Note that a polynomial has positive integral indices, therefore  \sqrt{x} +5 is not a polynomial.

The reason is that, \sqrt{x} +5=x^{\frac{1}{2} }+5 but \frac{1}{2} is not an integer.

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6 0
3 years ago
Select the correct answer.
Butoxors [25]

Answer:

Approximately 163 seconds (A)

Step-by-step explanation:

Line up 192 months on the x-axis with the line of best fit then run it across to the y-axis and it should be around 163 seconds.

8 0
3 years ago
4y-7-(y-7) find answer
andreyandreev [35.5K]
Answer is
3y
Step by step explanation
4 0
3 years ago
Read 2 more answers
I need help on thiss
Lapatulllka [165]
1. = 5 animals

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6 0
2 years ago
SEND HELP I HAVE NO IDEA HOW TO DO THIS
irina [24]
1) x² - x - 12 = 0

Factor it

(x-4)(x+3) = 0

Study the factors

x-4 = 0 -> x =4
x+3 = 0 -> x = -3

2) t = x²

x⁴ = (x²)²

t² + 3t - 4 = 0

Use quadratic formula:

(-b±√b²-4ac)/2a

(-3±√9+16)/2

(-3±5)/2

t1 = 2/2 = 1
t2 = -8/2 = -4 (not possible, we choose t1)

So x² = 1

Result: x = <span>±1

3) Square both sides

2x-4 = (x-6)</span>²

2x-4 = x²-12x+36

Take all terms to the left

2x - 4 - x² + 12x - 36 = 0

-x² + 14x - 40 = 0

x² - 14x + 40 = 0

Use quadratic formula:

(-b±√b²-4ac)/2a

(14±√196-160)/2

(14±6)/2

x1 = 10
x2 = 4

Let's check

√2(10) - 4 = 10 - 6
√20-4 = 4
√16 = 4
4 = 4 (OK)

√2(4) - 4 = 4 - 6

√8-4 = -2

√4 = -2

2 = -2 (NO)

So x = 10

4) Factor x²-9 = (x-3)(x+3)

So the common denominator would be (x-3)(x+3)

\frac{x(x+3)+x(x-3)}{(x+3)(x-3)} =  \frac{2}{(x+3)(x-3)}

Cancel out the denominators...

x+3 ≠ 0 -> x ≠ -3
x-3 ≠ 0 -> x ≠ 3

Take all members to the left

x(x+3)+x(x-3)-2 = 0

x²+3x+x²-3x-2 = 0

2x² - 2 = 0

2x² = 2

x² = 1

x = ±1
6 0
3 years ago
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