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balandron [24]
11 months ago
13

3x+7y=76 9y+5y=108 find x find y

Mathematics
1 answer:
klemol [59]11 months ago
8 0

In the given system of equations, the value of x is 7.334 and the value of y is 7.714

<h3>Solving system of linear equations</h3>

From the question, we are to solve the given system of linear equations

The given system of linear equations is

3x + 7y = 76               ------------ (1)

9y + 5y = 108             ------------ (2)

From equation (2), solve for y

9y+ 5y = 108

14y = 108

y = 108/14

y = 7.714

Substitute the value of x into equation (1), to determine the value of x

3x + 7y = 76

3x + 7(7.714) = 76

3x + 53.998 = 76

Subtract 53.998 from both sides of the equation

3x + 53.998 - 53.998  = 76 - 53.998

3x = 22.002

Divide both sides of the equation by 3

3x/3 = 22.002/3

x = 7.334

Therefore,

x = 7.334 and y = 7.714

Learn more on Solving system of linear equations here: brainly.com/question/13729904

#SPJ1

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Answer:

See explaination

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\frac{x+1}{x-1} = \frac{y+1}{y-1}

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let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

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\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

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for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

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