Answer:
The metal rod cannot fit into the rectangular crate
The maximum length that can fit is 2.71 m
Step-by-step explanation:
step 1
Find the diagonal of the base of the rectangular crate
Applying the Pythagoras Theorem
Let
d ----> the diagonal of the base
step 2
Find the diagonal of the crate
Let
D ----> the diagonal of the crate
where
d is the diagonal of the base
h is the height of the crate
we have
substitute the values
therefore
The metal rod cannot fit into the rectangular crate
The maximum length that can fit is 2.71 m
Convert 1 and 1/2 to eights to make it easier to subtract. 1 4/8 add 1 to 4/8
12/8 then subtract that by 7/8 straight across the numerator. That then equals 5/8
Step-by-step explanation:
(q and (not q or p)) = (q and not q) or (q and p) = false or q and p = q and p
(p and not (q and p)) = (p and (not q or not p)) =
= (p and not q) or (p and not p) = (p and not q) or false =
= p and not q
so, we have in total
(q and p) or (p and not q) = (p and q) or (p and not q).
this is p, because if p=false both brackets are false and therefore the whole expression is false. and if p=true, then one of the 2 brackets must be true, which makes the whole expression true.
JL=MK, therefore 2x+5=7x-40
5=5x-40
45=5x
9=x
7(9)-40= 63-40=23
Answer:
it is 20.5
Step-by-step explanation:
you need to add all of the numbers together
