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pickupchik [31]
3 years ago
10

What is the probability that in a class of 20 students, 2 of them will have the same birthday?

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0
There would be a 10% chance that they would have the same birthday
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You borrow $3,897 for a loan for college expenses with a 2.5% interest rate. How much interest is charged on the loan
belka [17]

Answer:

Amount of interest pay per year = $97.5 (Approx.)

Step-by-step explanation:

Given:

Amount borrow for college expenses = $3,897

Rate of interest = 2.5%

Find:

Amount of interest pay per year

Computation:

Using Simple interest formula;

Simple interest = Amount borrow x Rate of interest x number of year

Amount of interest pay per year = 3,897 x 2.5% x 1

Amount of interest pay per year = 3,897 x 0.025

Amount of interest pay per year = 97.425

Amount of interest pay per year = $97.5 (Approx.)

7 0
3 years ago
What is the answer to this problem
miv72 [106K]
10x10x10x10=10^4
10x10x10x10=10,000

6x10^5=6x100000
6x10^5=600000
7 0
3 years ago
Read 2 more answers
2w+2l=24 what is the value of l
valentinak56 [21]
If the question is 2w+2L=24 than the answer is 6-w=L
but if the question is 2w+21=24 the answer is w=3/2
3 0
3 years ago
Help me with A and B please
g100num [7]

Part A.

Ashwin had a 4-cm cube.

volume of cube = side^3

volume = (4 cm)^3 = 64 cm^3

Ashwin has 64 small cubes.

We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.

A. v = 2 * 4 * 7 = 28

B. v = 4 * 5 * 6 = 120

C. v = 5 * 5 * 4 = 100

D. v = 4 * 7 * 5 = 140

E. v = 3 * 5 * 4 = 60

Part A. answer: A, E

Part B.

Dora had a 5-cm cube.

volume of cube = side^3

volume = (5 cm)^3 = 125 cm^3

Dora has 125 small cubes.

We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.

A. v = 3 * 3 * 8 = 72

B. v = 3 * 4 * 5 = 60

C. v = 6 * 6 * 4 = 144

D. v = 5 * 8 * 4 = 160

E. v = 3 * 5 * 4 = 60

Part B. answer: A, B, E

6 0
3 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
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