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Travka [436]
3 years ago
7

3. Katryn has a bag of 150 pieces of candy. 58% of the candy

Mathematics
1 answer:
Vinvika [58]3 years ago
8 0

Answer:

90 she ate 90 of the pieces of candy

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Which sample is biased?<br>Please Answer!!
kicyunya [14]

Answer:

(Don’t take my word because I don’t want you to get the question wrong) I would go with a or b in my opinion. But choose the one you think is right.

Step-by-step explanation:

7 0
3 years ago
The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
3 years ago
Help? I’ll mark u brainliest
andrew-mc [135]

Answer:

11 because adjacent is basically next to and NKL is 12

Step-by-step explanation:

6 0
3 years ago
I will give brainliest
pshichka [43]

Answer:

They studied for a little more than an our. A

Step-by-step explanation:

Because if you multiply 4 on 2/3 you get 8/12, then add 8/12 and 7/12 together to get 15/12 simplified 1  3/12.

3 0
3 years ago
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Explain why the square root of a number is defined to be equal to that number to the 1/2 power<br>​
denis23 [38]

Answer:

Because square root is essentially the same thing as the power to a half

sqrt(x) is the same as (x)^1/2

4 0
3 years ago
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