Speed=distance / time ⇒ distance=time x speed
distance=d
time=t
speed= s
d=s*t
Distance traveled by Mr Guerrero, when his daugther left the house
Data:
s=40 miles/ hour
t=2 hours
d=40 miles/ hour * 2 hours= 80 miles
Total distance traveled by Mr Guerrero:
d=80 miles + 40 miles/hourt ⇒d=80+40t (1)
d=total distance.
s=speed.
t=time spent by Miranda for she overtook her father.
Distance traveled by Miranda.
data:
s=48 miles/ hour
d=total distance.
t=time spent by Miranda for she overtook her father.
d=48 miles/hour * t ⇒d=48t (2)
With the equations (1) and (2), we make an system of equations:
d=80+40t
d=48t
We can solve this system of equation by equalization method.
80+40t=48t
80=48t-40t
80=8t
t=80/8=10
d=48t
d=48*10=480
Answer: the thistance will be 480 miles.
Z4+x33[23+32)
JanalN
Uhajaia
Jain
Answer:
i not good at this but i think 2 6 18 54 could be the answer if not im so sorry
Step-by-step explanation:
no, more than one triangle could be made with these measures
sss
9514 1404 393
Answer:
BC ≈ 17.0 (neither Crow nor Toad is correct)
Step-by-step explanation:
The left-side ratio of (2+4)/4 = 3/2 suggests BC is 3/2 times the length DE. If that were the case, BC = (3/2)(11) = 16.5, as Crow says.
The right-side ratio of (5+9)/9 = 14/9 suggests that BC 9 is 14/9 times the length DE. If that were the case, BC = (14/9)(11) = 154/9 = 17 1/9 ≈ 17.1, as Toad says.
The different ratios of the two sides (3/2 vs 14/9) tell you that the triangles are NOT similar, so the length of BC cannot be found by referring to the ratios of the given sides.
Rather, the Law of Cosines must be invoked, first to find angle A (109.471°), then to use that angle to compute the length of BC given the side lengths AB and AC. That computation gives BC ≈ 16.971. (See the second attachment.)