Are these right ? I have changed it twice please help

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

What multiplication equation can you use to check the answer to the problem -32 divided by -4

Naddika [18.5K]

8x-4=-32 so thats an equation that you can use

5 0

2 years ago

Which is steeper, a slide that rises 3 feet for every 2 feet of run, or a sliding pole that rises 5 feet for every 3 feet of run

mezya [45]

Answer:

59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.

Step-by-step explanation:

Step 1

Express the angle of inclination as follows;

Tan∅=H/R

where;

∅=angle of inclination

H=vertical rise

R=distance of run

Step 2

Determine the angle inclination when;

H=3 feet

R=2 feet

replacing;

Tan∅=(3/2)=1.5

∅=Tan^(-1)(1.5)

∅=56.31°

Determine the angle inclination when;

H=5 feet

R=3 feet

replacing;

Tan∅=(5/3)=1.67

∅=Tan^(-1)(1.67)

∅=59.03°

59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.

6 0

2 years ago

A bee flies 20 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for fifteen minutes. Then i

Ksenya-84 [330]

A. The equation to find the distance of the flowerbed from the hive is: $\frac{x}{20}+\frac{x}{12}+900= 1200$ , where x is the distance.

B. The flowerbed is 2250 feet far from the hive.

Explanation

Suppose, the distance of the flowerbed from the hive is $x$ feet.

The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.

As, $Time=\frac{Distance}{Speed}$

So, the time taken by the bee to reach the flowerbed $= \frac{x}{20}$ seconds and the time taken to fly back to the hive $=\frac{x}{12}$ seconds.

The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.

So, the equation will be.......

$\frac{x}{20}+\frac{x}{12}+900= 1200\\ \\ \frac{3x+5x}{60}= 300\\ \\ 8x= 60*300\\ \\ 8x=18000\\ \\ x=\frac{18000}{8}=2250$

Thus, the distance of the flowerbed from the hive is 2250 feet.

5 0

3 years ago

Simplify the expression fraction with numerator of the square root of negative one and denominator of the quantity three plus ei

Ainat [17]

The right answer for the question that is being asked and shown above is that: "fraction with numerator negative 3 minus i and denominator 10." This is the simplified expression fraction with numerator of the square root of negative one and denominator of the quantity three plus eight times i minus the quantity two plus five times i.

5 0

3 years ago

Read 2 more answers