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3 years ago

Are these right ? I have changed it twice please help

Mathematics

1 answer:

tester [92]3 years ago

6 0

All correct accept "man" the word "man" goes to the long a side
you are all good
hopes this help :) :D :)

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pickupchik [31]

Answer:

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3 years ago

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Write a recursive rule for the sequence. Assume it starts with the 1st term. 10, 14, 18, 21...

Papessa [141]

Option D is correct. The correct option for the recursive formula is $f(0) =6;f(n)=f(n - 1)+4$

Given the sequence 10, 14, 18...

The first term is 10, hence

a1 = 10

The previous terms will be $a_{n-1}$

From the sequence, we can see that <em>4 is being added to the previous term to get the next term</em>. Hence the nth term will be expressed as:

$a_n = a_{n-1} + 4$

Get the term before the first term $a_0$

If n = 1

$a_1 = a_{1-1} + 4\\a_1 = a_{0} + 4\\a_0=a_1-4\\a_0=10-4\\a_0=6$

Hence the correct option for the recursive formula is $f(0) =6;f(n)=f(n - 1)+4$

Learn more here: brainly.com/question/18233843

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3 years ago

Choose the true statement -2<-3 , -2>-3 , -2=-3

larisa86 [58]

It's option 2) -2>-3 hope it helps you

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4 years ago

Find the required annual interest rate, to the

bezimeni [28]

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$1400\\ P=\textit{original amount deposited}\dotfill &\$1100\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &7 \end{cases}$

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kvasek [131]

answer is 130 use calculator

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