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3 years ago

Are these right ? I have changed it twice please help

Mathematics

1 answer:

tester [92]3 years ago

6 0

All correct accept "man" the word "man" goes to the long a side
you are all good
hopes this help :) :D :)

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Monica [59]

Answer:

52, 60, 68, 76..

Step-by-step explanation:

8 0

3 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

For which function is f(x) not equal to f-1(x)?

kobusy [5.1K]

Are there aby answer choices?

3 0

3 years ago

You are about to take the road test for your driver's license. You hear that only 38% of candidates pass the test the first t

OLga [1]

Answer:

Answers may vary but will most likely be close to 2.

Step-by-step explanation

Given:

first test:38%

second test:76%

SIMULATION FIRST TEST

Randomly select a 2-digit number.

If the digit is between 00 and 35 then you passed the test,else you did not pass the test.

SIMULATION SECOND TEST

Randomly select a 2-digit number.

if the digit is between 00 and 75 then you passed the test,else you did not pass the test.

SIMULATION TRIAL

Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.

Record the number of trials needed to pass the first or second test.

Repeat 20 times and take the average of the 20 recorded number of trials

(what is the sum of recorded values divided by 20).

Note:you will most likely obtain a result of about two trials needed.

7 0

3 years ago

This is my last question for the day please help

vladimir2022 [97]

Answer:

B: billie's solution is incorrect since she didnt

subtract 36 from both sides

Step-by-step explanation:

on the second step, she added 36 on the right.

This is incorrect because when changing one

side on an equation you must change the side

in the same way.

5 0

3 years ago

Read 2 more answers