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Yakvenalex [24]
3 years ago
13

The explicit rule for a sequence is an=14-9n What is the recursive rule for the sequence?

Mathematics
2 answers:
galina1969 [7]3 years ago
7 0

The explicit rule for the sequence is a_{n}=14-9n

Let us put n=1, we get

a_{1}=14-(9 \times 1)=5

Now let n=2,

a_{2}=14-(9 \times 2)=-4

Let n=3,

a_{3}=14-(9 \times 3)=-13

Similarly, in this manner we obtain a sequence as

5, -4, -13, -22,.....

Since we can clearly observe that the first term is '5' and common difference is '-9'.

So, we get recursive rule for the sequence as:

a_{n}=a_{n-1}-9 , where a_{1}=5.

natulia [17]3 years ago
6 0
You have to add it then divide it 
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PLEASE ANSWER + BRAINLIEST!!!
grandymaker [24]

Width is 11k^2

Length is 5k^3 + 2k^2

Look at: https://www.wyzant.com/resources/answers/392371/what_is_the_length_and_width_of_the_rectangle

5 0
3 years ago
Work out 12+8÷(9-5) 0.018÷0.06 Express as single fraction 5/7÷2/5
Anettt [7]

Step-by-step explanation:

I don't know if the first set of numbers is all in one set, but I'll do my best to give you an answer.

Really all you need to do is use PEMDAS for the first question.

(Parentheses, exponents, multiply, divide, add, subtract. In that order)

1 2 + 8 \div (9 - 5) \\ 12 + 8 \div 4 \\ 12 + 2 \\ 14

Then to simplify that fraction next to it, notice that 0.018 is 3x 0.06.

that's a 3:1 ratio, so it ends up simplifying to this:

\frac{3}{1}

Lastly, to solve the division of that fraction. If you divide by a fraction, you multiply whatever it's dividing by its inverse.

So...

\frac{5}{7}  \div  \frac{2}{5}  \\  \frac{5}{7}  \times  \frac{5}{2}  \\  \frac{25}{14}

7 0
3 years ago
According to the bar graph, which attribute is under investigation?
Kryger [21]
The answer is A) the height of students 
5 0
3 years ago
D=a/a+12*M. The adult weighs 75 kg. Calculate the adults weight in kilograms to pounds. Round final answer 2 decimal places
andrew-mc [135]

An adult with a weight of 75 kilograms have an <em>equivalent</em> weight of 165.60 pounds.

<h3>How to convert kilograms to pounds</h3>

Herein we have an application of <em>unit</em> conversions between <em>weight</em> units, from kilograms to pounds. Unit conversions follow this <em>direct proportional</em> formula:

y = k · x

Where:

x - Weight in kilograms

y - Weight in pounds

k - Conversion ratio

If we know that x = 75 kg and k = 2.208 lb/kg, then the weight of the adult in pounds is:

y = (2.208 lb/kg) · (75 kg)

y = 165.6 lb

An adult with a weight of 75 kilograms have an <em>equivalent</em> weight of 165.60 pounds.

To learn more on weight units: brainly.com/question/18762697

#SPJ1

5 0
2 years ago
I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 &lt; c &lt; 2$ $\bullet$ $c$ can be written as a fraction wit
makkiz [27]

Answer:

Possible answer: \displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6.

Step-by-step explanation:

Rewrite the bounds of c as fractions:

The simplest fraction for 1.5 is \displaystyle \frac{3}{2}. Write the upper bound 2 as a fraction with the same denominator:

\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}.

Hence the range for c would be:

\displaystyle \frac{3}{2} < c < \frac{4}{2}.

If the denominator of c is also 2, then the range for its numerator (call it p) would be 3 < p < 4. Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than 2.

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}.

\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}.

At this point, the difference between the numerators is now 2. That allows a number (7 in this case) to fit between the bounds. However, \displaystyle \frac{1}{c} = \frac{4}{7} can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}.

\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}.

\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}.

\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}.

\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}.

\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}.

It is important to note that some expressions for c can be simplified. For example, \displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5} because of the common factor 2.

Apparently \displaystyle c = \frac{16}{10} = \frac{8}{5} works. c = 1.6 while \displaystyle \frac{1}{c} = \frac{5}{8} = 0.625.

8 0
4 years ago
Read 2 more answers
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