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Oduvanchick [21]

2 years ago

12

Please answer this question now. Giving brainliest to anyone who answers

1 answer:

baherus [9]2 years ago

6 0

Line p is perpendicular to S and the equation is y=x +3 which is D

You might be interested in

What values for q (0 ≤q≤2π)<br> satisfy the equation?<br><br> 22√sin q + 2 = 0

Vesna [10]

Answer:
$\frac{3 \pi }{4}$ , $\frac{7 \pi }{4}$

Explanation:
2√2 sin(q) + 2 = 0
2√2 sin(q) = -2
sin(q) = $\frac{-2}{2 \sqrt{2} }$
sin(q) = $\frac{- \sqrt{2} }{2}$

Now, we know that:
sin (45) = $\frac{ \sqrt{2} }{2}$

From the ASTC rule, we know that the sine function is negative in the third and fourth quadrant.
This means that:
either q = 90 + 45 = 135° which is equivalent to $\frac{3 \pi }{4}$
or q = 270 + 45 = 315° which is equivalent to $\frac{7 \pi }{4}$

Hope this helps :)

6 0

3 years ago

Read 2 more answers

You are selling tickets to a play. You have sold (3t+2) tickets for $5 each and (2t+5) tickles for $7each. Write an expression t

yKpoI14uk [10]

Expression = 5(3t+2)+7(2t+5)
=15t+10+14t+35
=29t+45 is the answer

5 0

3 years ago

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

2 years ago

8-1×0+2÷2=? It looks easy, so many different results.

kvasek [131]

You have to use PEMDAS.

$8-1*0+2/2 \\ \\ 8-0+2/2 \\ \\ 8-0+1 \\ \\ 8+1 \\ \\ 9$

8 0

2 years ago

Read 2 more answers

What is x in the equation in -4(3x+7)= 4

Nana76 [90]

Answer:

-12x-28=4

-12x=32

x=-16/3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers