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Mrrafil [7]
3 years ago
10

Use the distribute property to rewrite the following expression (6+15). your final answer should be in the form _(_+_).

Mathematics
1 answer:
Veronika [31]3 years ago
5 0

Answer:

3(2+5)

Step-by-step explanation:

The common number that both 6 and 15 can be divided by is 3

3x2=6 and 3x5=15

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Step-by-step explanation:

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In a class, 14 out of 20 students pack their lunches. What percent of students pack their lunches? $$
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Read 2 more answers
PLEASE NEED HELP PLZ
never [62]

Answer:

Step-by-step explanation:

Hi, saw your comments, TY :)

this is super tricky b/c they tell us at the top that the triangles are similar so we have to know that we can use that triangle relation to make an equation. It just seem like to me, that you'd not see this  "connection"  where

the smaller triangle is CDE and the bigger one is QPR , so the side can be the lower case of those letters..  the side opposite of the angle is the lower case letter like the angle, soo

p = 2x + 16

r = 33

e = 8

c = 6

then the triangles have that similar triangle relation, of

p = e

r = c

so the fractional relations ship between  e/p  = c /r  you could also make it work by doing  p/e = r/c   but.. you have to keep the bigger triangle and smaller one in the same place for each fraction.  So it's important to keep that clear, which is which

let's use the fractions this way

p/e = r/c  , it seems easiest to me, plug in the values,  

2x + 16 / 8 = 33 / 6  ( now some algebra,  where all mistakes happen :P)

2x + 16 = 8 ( 33 / 6 )   ( times 8 on both sides )

2x + 16 = 4 ( 33 / 3 )         ( I just reduced by 2 )

2x + 16 = 4 ( 11 )  

2x + 16 = 44

2x  = 44 - 16

2x = 28  

x = 14                  ( divide by 2 on both sides )

Yay,  you can check to see if it's right by plugging 14 in for x and seeing if the  p/e = r/c relationship works, I did, and it does :P  but try it just for practice :)  

4 0
4 years ago
X^2-xy-3x+2+2y <br>factorize this​
joja [24]

Answer:

it  2x

Step-by-step explanation:

because

6 0
3 years ago
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