4 years ago

Write a number that has a zero in the tens place.Draw a quick picture for your number.

Mathematics

1 answer:

dlinn [17]4 years ago

4 0

Zero in the ten's place.

10

1 - one's place

0 - ten's place

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Geomtry plzz help 15 points

luda_lava [24]

Answer:

False.

Step-by-step explanation:

The sides of a triangle rule asserts that the sum of the lengths of any two sides of a triangle has to be greater than the length of the third side. However, 8+6=14 is less than 15. Hence, the triangle cannot be formed.

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3 years ago

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Select all possible solutions for 2x+7 ≤ 3x-5

Leto [7]

2x+7 <= 3x-5

subtract 2x from each side

7 <= x-5

add 5 to each side

12 <= x

x must be greater than or equal to 12

12 18 24 and 107 are possible solutions

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4 years ago

A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif

VashaNatasha [74]

Answer:

(A)

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

For any $x$ you are looking for the probability $P(X \geq x)$ which is

$P(X \geq x) = \int\limits_{-\infty}^{x} 1.25(1-t^4) dt = \int\limits_{0}^{x} 1.25(1-t^4) dt = 1.25x - 0.25x^2$

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

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4 years ago

A box contains 15 transistors, 5 of which are defective. if 5 are selected at random, find the probability that

Nikolay [14]

The answer is 1/3 because 5/15=1/3

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4 years ago

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Question 8

MrRa [10]

Answer:

last, y=-1/4x+2

Step-by-step explanation:

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3 years ago