Question

I need help please......

Answer 1

Ah so the length of the minute hand is the radius. 

Given that the raduis is 14mm, the area of the watch face can be found with A=$\pi r^2$

Therefore 
A=$\pi r^2$
A=$\pi 14^2$
A=$196 \pi$

The watch face has an area of $196 \pi$

Answer 2

A clocks minute hand makes one revolution (360 degrees) for every hour. That means we can find the area as normal using the formula:

$\pi r^2$, where r is the radius.

pi*14^2
=pi*196
=196pi

:)