Answer: The area of the regions covered by grass is approximately 313.375 sq ft.
Step-by-step explanation:
Given: A company is building a new park in the shape of a circle with a 25 ft diameter.
Then radius = ![\dfrac{25}{2}=12.5\ ft](https://tex.z-dn.net/?f=%5Cdfrac%7B25%7D%7B2%7D%3D12.5%5C%20ft)
Required area = Area of circle - Area of rectangle + Area of triangle
Formula: Area of circle = ![\pi r^2](https://tex.z-dn.net/?f=%5Cpi%20r%5E2)
Area of rectangle = length x width
Area of triangle = 0.5 x base x height
Area of circle = ![(3.14)(12.5)^2=490.625\ \text{ft}^2](https://tex.z-dn.net/?f=%283.14%29%2812.5%29%5E2%3D490.625%5C%20%5Ctext%7Bft%7D%5E2)
Area of rectangle = 20 ft x 10ft = 200 ft²
Area of triangle = 0.5 x 7 x 6.5 = 22.75 ft²
Required area = 490.625 -200+22.75 = 313.375 ft²
Hence, The area of the regions covered by grass is approximately 313.375 sq ft.
Answer:
zero, because the discriminant is negative
Step-by-step explanation:
By writing the quadratic formula, we have the discriminant written in the root as;
b^2-4ac
Now, given the expression, we can see that the discriminant here is -19
What this mean is that we have a negative discriminant
Hence, we can conclude that the roots are complex and as such, none of the roots are real
<span>A relation is a set of inputs and outputs, often written as ordered pairs (input, output). </span>
The answer is Pythagorean
The Pythagorean theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
Answer:
D. tan <em>0</em><em> </em>= 8/15 and A. sec <em>0</em><em> </em>= 17/15
Step-by-step explanation:
Cos <em>0</em> = adjacent/ hypotenus
Adj = 15 and Hyp =17
Using pythagoras theory
Opp^2 = 17^2 - 15^2
Opp^2 = 289 - 225
Opp^2 = 64
Therefore <em>Opp</em><em> </em><em>=</em><em> </em><em>8</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>square</em><em> </em><em>root</em><em> </em><em>of</em><em> </em><em>6</em><em>4</em>
tan <em>0</em><em> </em>= opp/adj
tan <em>0</em><em> </em><em>=</em><em> </em>8/15
Sec <em>0</em><em> </em>is the multiplicative inverse of cos <em>0</em>