Math help I need help with all 4 questions

Mathematics

1 answer:

avanturin [10]3 years ago

4 0

its hard to see txt an i can get u a app for it

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Pls help middle school math

uranmaximum [27]

Given ,

5<x<10 and 8<y<19

For y-x,

8-5<y-x<19-10

3<y-x<9

8 0

3 years ago

Expand and simplify (x+5)(x-2)

salantis [7]

Answer:

${x}^{2} - x - 12 = (x + 3)(x - 4)$

${x}^{2} + 3x + 2 = (x + 2)(x + 1)$

${x}^{2} + 3x - 10 = (x + 5)(x - 2)$

Step-by-step explanation:

F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

${x}^{2} - x - 12 = {x}^{2} - 4x + 3x - 12$