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olga55 [171]
3 years ago
10

The perimeter of a rectangular field is 52 yards. The length is 4 more yards than the width. Find the length and width of the fi

eld.
Question 13 options:

A)

Length = 9 yards; Width = 4 yards

B)

Length = 12 yards; Width = 9 yards

C)

Length = 8 yards; Width = 13 yards

D)

Length = 15 yards; Width = 11 yards
Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0

:) Brainliest pls?

Answer:

D.

Width = 11 yards

Length = 15 yards

Step-by-step explanation:

P = 2(l + w)

Consider the width to be x.

The length would then be x+4.

We know that P = 52 yd

52 = 2(x + x + 4)

52 = 2(2x + 4)

52 = 4x + 8 (Subtract 8 from both sides)

44 = 4x (Divide both sides by 4)

x = 11

The width is x, so the width is 11 yards.

The length is x+4, so the length is 15 yards.

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Help me please and thank you
fiasKO [112]

Answer:

$51.70

Step-by-step explanation:

I don't know how to explain it actually so I am just going to do this...

y= 0.1(x + 20) +7

y=0.1x + 2 + 7

y=0.1x +9

y=0.1(427)+9

y=42.7+9

y=51.7

So, maybe the answer is $51.70.

7 0
3 years ago
More than 450 students traveled to a state park for a field trip. The school allowed 6students to travel by car, and the rest tr
ki77a [65]

Answer:


Step-by-step explanation:

Let b= number of people per bus

 

10b + 5 > 450

 

10b > 445

b > 44.5

Minimum per bus is 45 students

6 0
3 years ago
72 is what percent of 45?<br><br> __ = p/100<br><br> p= __
Marta_Voda [28]

Answer:

72 of 45 is 160%

Step-by-step explanation:

72 of 45 can be written as:

\frac{72}{45}

To find percentage, we need to find an equivalent fraction with denominator 100. Multiply both numerator & denominator by 100

\frac{72}{45} *\frac{100}{100}

=(\frac{72*100}{45} )*\frac{1}{100} =\frac{160}{100}

Therefore, the answer is 160%

If you are using a calculator, simply enter 72÷45×100 which will give you 160 as the answer.

3 0
2 years ago
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At least 50 Feet or Taller. Depending on the distance between each Floor.
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Miller has a painting that is 4 ft by 8 ft. What will the dimensions of the painting be if he scales it down by a factor of one-
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