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Ulleksa [173]
4 years ago
10

Solve for missing angle.Justify and explain your calculations

Mathematics
1 answer:
myrzilka [38]4 years ago
3 0
The missing angle would be 68 because the the triangles can be alternate exterior
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What is the equation of this graphed line?
Tems11 [23]

Answer: y=-9/8x+7

Step-by-step explanation:

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3 years ago
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I will mark branlest if you are right
schepotkina [342]

Answer:

1) y=(-1/4)x+(11/4)

2) y=(4)x-33

3) y=(2/3)x-11/3

4) y=(5)x-2

5) y=(3)x-7

6) y=(-1/4)x+(6)

Step-by-step explanation:

1) y=mx+b  3=(-1/4)(-1)+b  b= 11/4

2) y=mx+b  -5=(4)(7)+b  b= -33

3) y=mx+b  -5=(2/3)(-2)+b  b= -11/3

4) y=mx+b  3=(5)(1)+b  b= -2

5) y=mx+b  -1=(-3)(-2)+b  b= -7

6) y=mx+b  7=(1/4)(4)+b  b= 6

6 0
4 years ago
7 tens x 10 in standard form ​
rosijanka [135]

Answer:

700

Step-by-step explanation:

7 tens is 70. 70*10=700.

6 0
3 years ago
The roots of a quadratic equation ax2+bx+c=0 are 1+i 5 and 1−i 5 . Find possible values of a, b and c.
Anarel [89]

Answer:

Step-by-step explanation:

If the roots are 1 + 5i and 1 - 5i, then you need the factors that result from those roots.  They are (x - 1 + 5i) and (x - 1 - 5i).  Now what you do with those is FOIL them out.  Doing that gives you the following:

x^2-x+5ix-x+1-5i-5ix+5i-25i^2 (what a mess, huh?)

The good thing is that several of those terms cancel each other out.  +5ix cancels out the -5ix; -5i cancels out the 5i; and the 2 -x terms combine to -2x.  That leaves you with:

x^2-2x-25i^2

Obviously you're in the section in math that deals with complex (imaginary) numbers so you should know that i-squared is equal to -1.  Making that replacement:

x^2-2x+25

a = 1, b = -2, c = 25

6 0
4 years ago
Read 2 more answers
What is the value of x in the diagram?
dalvyx [7]

Answer:

x = 30

Step-by-step explanation:

here 50 is hypotenuse as it is opposite of 90 degree.

x and x + 10 are the two other smaller sides of a right angled triangle respectively.

using pythagoras theorem,

a^2 + b^2 = c^2

x^2 + (x + 10)^2 = 50^2

x^2 + x^2 + 20x + 100 = 2500

2x^2 + 20x + 100 = 2500

2x^2 + 20x + 100 - 2500 = 0

2x^2 + 20x - 2400 = 0

2(x^2 + 10x - 1200) = 0

x^2 + 10x - 1200 = 0

x^2 + (40 - 30) - 1200 = 0

x^2 + 40x - 30x - 1200 = 0

x(x + 40) - 30(x + 40x) = 0

(x + 40)(x - 30) = 0

either x + 40 = 0          OR x - 30 = 0

x = 0 - 40

x = -40

x - 30 = 0

x = 30

x = -40,30

since the length and distance is not measured in negative ur answer will be 30

credit goes to sreedevi102

thank u very much . At first i was wrong and giannathecookie i m really sorry

3 0
3 years ago
Read 2 more answers
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