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Orlov [11]
2 years ago
6

What is the best estimate for the mass of a bicycle?

Mathematics
2 answers:
Akimi4 [234]2 years ago
6 0
About 100g is correct
Natasha2012 [34]2 years ago
5 0

Answer:

10kg

Step-by-step explanation:

It can't be 10g or 100 g and 1kg cause those are too easy to carry

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What can be used as a reason in a two-column proof?
erik [133]
Two column proofs are organized into statement and reason columns. Each statement must be justified in the reason column. The reason column will typically include "given", vocabulary definitions, and theorems.

Therefore, w<span>hat can be used as a reason in a two-column proof are:

Postulates

Definitions</span>
8 0
3 years ago
Read 2 more answers
Hayden is building toy cars. Each car needs 4 wheels. How many wheels will Hayden use to build 3 toy cars?
ycow [4]

Answer:

12

Step-by-step explanation:

Three cars each need 4 wheels, so that is...

4 + 4 + 4 wheels, which is 12 wheels

8 0
2 years ago
A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is
Scorpion4ik [409]

Answer:

  • 26 ounces of 55% solution
  • 104 ounces of 80% solution

Step-by-step explanation:

Let x represent the quantity of 80% solution. Then 130-x is the amount of 55% solution. The total amount of salt in the mix is ...

  0.80x +0.55(130 -x) = 0.75·130

  0.25x = 0.20·130 . . . . . . . subtract 0.55(130)

  x = 0.20/0.25(130) = 104

  130-x = 26

She should use 26 ounces of 55% solution and 104 ounces of 80% solution.

5 0
3 years ago
Amuseumcharges forgeneraladmission and exhibitions. Admission and 3 exhibitionscosts $45. Admission and 5 exhibitionscosts $65.
leonid [27]

Answer:

The price of the admission is 15.

Step-by-step explanation:

From the information given, you can write the following equations:

a+3e=45 (1)

a+5e=65 (2), where:

a is the admission cost

e is the exhibition cost

First, you can solve for a in (1):

a=45-3e (3)

Second, you can replace (3) in (2):

45-3e+5e=65

45+2e=65

2e=65-45

2e=20

e=20/2

e=10

Finally, you can replace the value of e in (3):

a=45-3e

a=45-3(10)

a=45-30

a=15

According to this, the price of the admission is 15.

3 0
3 years ago
Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?
Yanka [14]

Answer:

Step-by-step explanation:

\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.

\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\

(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+  \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.

8 0
1 year ago
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