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3 years ago

6

Why does on emole of carbon have a smaller mass than one mole of sulfur? how are the atomic structures of these elements differe

nt?

1 answer:

Setler79 [48]3 years ago

8 0

Because carbon has a molar mads of 12 (6 protons and 6 neutrons) while sulfur has a molar mass of 16 (8 protons and 8 neutrons)

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In lipid bilayers, there is an order-to-disorder transition similar to the melting of a crystal. Comparing a lipid bilayer that

prisoha [69]

Answer:

The lipid bilayer made up of Palmitic acid will have a higher melting transition temperature

Explanation:

The one with a higher melting transition temperature is the lipid layer with a higher melting temperature

Melting temperature of palmitoleic acid = -0.5°C

Melting temperature of palmitic acid = 62.9°C

Hence the lipid bilayer made up of Palmitic acid will have a higher melting transition temperature

6 0

3 years ago

Please help fast<br>I WILL MARK YOU AS BRAINLIEST

Elan Coil [88]

Answer:

c

Explanation:

all the atoms must be balanced.

3 0

3 years ago

Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or

Ahat [919]

Answer :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

Now we have to determine the oxidation state of the elements in the compound.

(a) $H_2SO_4$

Let the oxidation state of 'S' be, 'x'

$2(+1)+x+4(-2)=0\\\\x=+6$

Hence, the oxidation state of 'S' is, (+6)

(b) $Ca(OH)_2$

Let the oxidation state of 'Ca' be, 'x'

$x+2(-2+1)=0\\\\x=+2$

Hence, the oxidation state of 'Ca' is, (+2)

(c) $BrOH$

Let the oxidation state of 'Br' be, 'x'

$x+(-2)+1=0\\\\x=+1$

Hence, the oxidation state of 'Br' is, (+1)

(d) $ClNO_2$

Let the oxidation state of 'N' be, 'x'

$-1+x+2(-2)=0\\\\x=+5$

Hence, the oxidation state of 'N' is, (+5)

(e) $TiCl_4$

Let the oxidation state of 'Ti' be, 'x'

$x+4(-1)=0\\\\x=+4$

Hence, the oxidation state of 'Ti' is, (+4)

(f) $NaH$

Let the oxidation state of 'Na' be, 'x'

$x+(-1)=0\\\\x=+1$

Hence, the oxidation state of 'Na' is, (+1)

4 0

3 years ago

An acid is hydrogen and one or more nonmetals. <br><br> Select one:<br> True<br> False

dlinn [17]

Answer:

true

Explanation:

hope this helps!

brainliest please

have a great day

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please no reporting. (it makes me sad)

6 0

2 years ago

Calculate the ph of a buffer solution that contains 0.25 m benzoic acid (c6h5co2h) and 0.15 m sodium benzoate (c6h5coona). (ka =

zhannawk [14.2K]

Hello!

To solve this problem we'll use the Henderson-Hasselbach equation, but first we need the vale for the pKa of Benzoic acid, which is pKa= -log(Ka)=4,19

Now, we apply the equation as follows:

$pH=pKa + log ( \frac{[C_6H_5COONa]}{[C_6H_5COOH]} )=4,19+log( \frac{0,15M}{0,25M} )=3,97$

So, the pH of this solution of Sodium Benzoate and Benzoic Acid is 3,97

Have a nice day!

4 0

3 years ago

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