Answer:
A
Explanation:
Remember the number of valence electrons represent the group number. As shown in figure, there is only one electron in the valence shell. Therefore, this element belongs to group 1 elements also called as Alkali metals.
Furthermore, the number of electrons in a neutral atom equals number of protons. Hence, there are 11 protons in this element.
Also, number of protons equal atomic number therefore, the atomic number of this element is 11. And, by checking periodic table, the element having atomic number 11 is Sodium (Na).
Hey there!
There are 6.022 x 10²³ particles in 1 mole.
We have 3.55 moles.
6.022 x 10²³ x 3.55
2.14 x 10²⁴
This is how many particles we have.
NaCl has 2 atoms for every unit.
So we multiply this by 2.
2 x 2.14 x 10²⁴ = 4.28 x 10²⁴
There are 4.28 x 10²⁴ atoms in 3.55 moles of sodium chloride.
Hope this helps!
Hello! Before I answer to your question, please be sure to include a picture or else a report will be filed for your question would be commenced. You are lucky I have this for my homework tonight and I figured it out. Thank you:
The answer to your question would be as followed:
The most precise measurement for the cylinder you are mentioning is <em><u>B. 43.0mL</u></em>
The production of manganese peroxidase (MnP) by Irpex lacteus, purified to electrophoretic homogeneity by acetone precipitation, HiPrep Q and HiPrep Sephacryl S-200 chromatography, was shown to correlate with the decolorization of textile industry wastewater. The MnP was purified 11.0-fold, with an overall yield of 24.3%. The molecular mass of the native enzyme, as determined by gel filtration chromatography, was about 53 kDa. The enzyme was shown to have a molecular mass of 53.2 and 38.3 kDa on SDS-PAGE and MALDI-TOF mass spectrometry, respectively, and an isoelectric point of about 3.7. The enzyme was optimally active at pH 6.0 and between 30 and 40 degrees C. The enzyme efficiently catalyzed the decolorization of various artificial dyes and oxidized Mn (II) to Mn (III) in the presence of H(2)O(2). The absorption spectrum of the enzyme exhibited maxima at 407, 500, and 640 nm. The amino acid sequence of the three tryptic peptides was analyzed by ESI Q-TOF MS/MS spectrometry, and showed low similarity to those of the extracellular peroxidases of other white-rot basidiomycetes.
Answer:
The molar mass of the diprotic acid is 90.10 g/mol.
Explanation:
The acid is 25.0 mL of this solution required 11.1 mL of 1.00 KOH for neutralization.
To calculate the concentration of acid, we use the equation given by neutralization reaction:
( neutralization )
where,
are the n-factor, molarity and volume of diprotic acid
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Molarity of acid solution = 0.222 M =0.222 mol/L
Volume of original solution = 250 mL = 0.250 L ( 1 mL = 0.001 L)
Moles of diprotic acid in 0.250 L solution :
Mass of diprotic acid = m = 5.00 g
The molar mass of the diprotic acid is 90.10 g/mol.
