Answer:
Step-by-step explanation:
Let the 4 greatest numbers be, A, B, C D
(A + B + C + D)/4 = 8
Total sum = 4 × 8
= 32
Let the 4 lowest numbers be, D, E F G,
(D + E + F + G)/4 = 20
Total number = 4 × 20
= 80
Hence, the difference between the sums of the 3 greatest number and the 3 smallest numbers:
A, B, C and E, F, G
= D + (E + F + G) - (A + B + C) - D
= (E + F + G) - (A + B + C)
= 80 - 32
= 48.
