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777dan777 [17]
3 years ago
9

It was 55 degrees fahrenheit outside until the temperature increased 20 degrees fahrenheit. Which number is the addictive invers

e of the temperature increase?
Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0
Try using this
https://www.almanac.com/content/temperature-conversion
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(1 point) Find the limit, if it exists, or type DNE if it does not exist. A. lim(x,y)→(0,0)(x+5y)2x2+25y2=lim(x,y)→(0,0)(x+5y)2x
statuscvo [17]

Answer:

A. DNE. The limit does not exist.

B. The limit is 0

Step-by-step explanation:

A. lim(x,y)→(0,0)[(x + 5y)/(2x² + 25y²)]

Along the x axis, y = 0, the limit becomes:

lim(x)→(0)[x/2x²]

= lim(x)→(0)[1/2x] = infinity

Along the y axis, x = 0, the limit becomes

lim(y)→(0)[5y/25y²]

= lim(y)→(0)[1/5y] = infinity

DNE

B. lim(x,y)→(0,0)[(2x³ + 7y³)/(x² + y²)

Putting x = rcosθ, and y = rsinθ, the limit becomes

lim(r)→(0)[(2r³cos³θ + 7r³sin³θ)/(r²cos²θ + r²sin²θ)]

Because cos²θ + sin²θ = 1, the limit becomes:

= lim(r)→(0)[r³(2cos³θ + 7sin³θ)/r²]

= lim(r)→(0)[r(2cos³θ + 7sin³θ)]

= 0

The limit is 0

4 0
3 years ago
What is the interquartile range of the data set (WILL MARK BRAINLIEST)
mixas84 [53]

20,25,30,30,31,40,41,49

median=30.5

Q¹= 27.5

Q³=40.5

40.5-27.5= 13 IQR = 13

4 0
3 years ago
−\frac{7}{10} ÷\frac{2}{5}
bazaltina [42]
$$ −\frac{7}{10} \div\frac{2}{5}= \frac{-7}{4} $$ . totally answer. I hope helping with this answer
3 0
3 years ago
Need help with formula. Population of people is 5.3 per square mile and is 39 thousand square mile in size. What is the populati
VladimirAG [237]

Answer:

P = 5.3x = 206,700

Step-by-step explanation:

P = population

P = 5.3x, where x is the square miles

p = 5.3(39000) = 206,700

5 0
3 years ago
On the first day of​ June, there were about 17.71 h of daylight in a city. Five months​ later, there were about 5.30 h of daylig
Andru [333]

Answer:

Percentage increases and decreases, are found by setting the problem up proportionally.

 

You are trying to find what percentage of 17.37 is 8.30 first.

 

so What %/100 = 8.30/17.37

 

Now define a variable:

 

Let x = What%  

 

x/100 = 8.30/17.37

17.37x = 830

x = 830/17.37

x ≈ 47.78

 

8.30 is approximately 47.78% of 17.37, so the percentage decrease is 100% - 47.78% = 52.22%

The percentage decrease is approximately 52.22%

7 0
3 years ago
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