Notice that you are given an isosceles right-angle triangle to solve, since each of its two acute angles measures $45^o$ . Then such means that the sides opposite to these acute angles (the so called "legs" of this right angle triangle) must also be of the same length (x).

We can then use the Pythagorean theorem that relates the square of the hypotenuse to the addition of the squares of the triangles legs:

$(\sqrt{7})^2=x^2+x^2\\7=2\,x^2\\x^2=\frac{7}{2} \\x=+/-\sqrt{\frac{7}{2}} \\x=+/-\frac{\sqrt{14} }{2}$

We use just the positive root, since we are looking for an actual length. then, the requested side is:

$x=\frac{\sqrt{14} }{2}$

6 0

2 years ago

How do you do number 9?

Ket [755]

I think you just add all the sides even the ones you don't see. The left side of the shape is 6m as well as the right. and the same with the 4s. The answer is 36.

3 0

3 years ago

Read 2 more answers

A warehouse store sells 6.5 ounce cans of tuna in packages of 5. A package of 5 cans cost $11.05. The store also sells 5.5 ounce

cluponka [151]

Answer:

6.5-once cans is the best buy

6 0

3 years ago

https://tex.z-dn.net/?f=%286%29%5C+%5C+%5C+f%28x%29%3Dax%5E2%5C+%5C+%5C+and%5C+%5C+%5C+f%282%29%3D48%5C%5C.%5C+%5C+%5C+%5CRighta

snow_tiger [21]

Answer: