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GenaCL600 [577]
4 years ago
15

Convert y + 1 = 3/4 (x - 16) to standard form.

Mathematics
1 answer:
Archy [21]4 years ago
7 0
3x/4-y=13 or choice B
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Please I really need help
Lubov Fominskaja [6]

Answer:

a: 130

b: 130

c: 50

Step-by-step explanation:

a straight line has an angle of 180, so those two angles are going to add up to 180. and opposite angles are equivalent

6 0
3 years ago
Read 2 more answers
Compute the exact interest on $5,870 at 12% if the money is borrowed from June to December of the same year.
yawa3891 [41]

Answer:

The exact interest on $5,870 at 12% is $410.9

Step-by-step explanation:

From the information provided we know that

Principal amount: $5,870

Interest rate: 12% -> 0.12

Time: 7 months (From June to December)

When you know the principal amount, the rate, and the time, the amount of interest can be calculated by using the formula:

I=P\cdot r\cdot t

where P is principal, r is the rate of interest and t is the time in years.

We need to convert the 7 months into 1 year.

7 \>months \cdot \frac{1 year}{12 months} = \frac{7}{12} year

Now we can use the above formula

I=P\cdot r\cdot t=5870\cdot 0.12 \cdot \frac{7}{12} \\I = 0.12\cdot \frac{7\cdot \:5870}{12}\\I = 0.12\cdot \frac{20545}{6}\\I = \frac{2465.4}{6}\\I = 410.9

Therefore the exact interest on $5,870 at 12% is $410.9

7 0
3 years ago
In​ 1990, the average math SAT score for students at one school was 498. Five years​ later, a teacher wants to perform a hypothe
mojhsa [17]

Answer:

A. Fail to reject the claim that the average math SAT score is 498 when in fact it is not 498.

Step-by-step explanation:

Type II Error:

A type II error happens when there is a non-rejection of a false null hypothesis.

In this question:

The null hypothesis is H0​:μ=498.

Since there is a type II error, there was a failure to reject the claim that the average math SAT score is 498 when in fact it is not 498, and thus, the correct answer is given by option A.

6 0
3 years ago
Can someone please help me with these questions!! Thanks,
fiasKO [112]

6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1

6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)

6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)

6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²

8 0
3 years ago
Tell whether the angles are adjacent, vertical, complementary, or supplementary. Then find the value of x
loris [4]

x=70 vertical opposite

3 0
2 years ago
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