Convert y + 1 = 3/4 (x - 16) to standard form.

Which class of trailer hitch is best suited for a boat and its equipment weighing less than 2,000 pounds?

alexira [117]

Class I

Trailer hitches are divided into different classes on the basis of the weight that they will be supporting. The classes are Class I - V, after which the classes are Xtra Duty and finally the Commercial Duty class, which has the ability to support 20,000 lbs.

4 0

3 years ago

A self-serve car wash charges $5.32 to use its facilities, plus an additional $0.84 for each minute the customer is at the self-

iragen [17]

B. 9.52
All you have to do is create an equation:
5.32+.84(5)

4 0

3 years ago

Read 2 more answers

IT IS 2AM AND ITS DUE IN LIKE AN HOUR PLEASE HELP

Andreas93 [3]

13) As they’ve given the zeros, you can use those to create factors. Since the zeros are x=-1, x=-3, and x=4, by making the right side 0 in each equation, you get the factors (x+1), (x+3), and (x-4). Then, you can multiply those factors using box method or FOIL or whichever method you prefer. By multiplying (x+1) and (x+3), I got x^2+4x+3. Then, I multiplied that by (x-4) to get x^3-13x-12, which is your final answer.

14) Using the same steps in 13, I found the factors. As the zeros are x=-6 and x=0, I got the factors (x) and (x+6). Then, I multiplied them and got x^2+6x, which is the answer.

15) x=1, x=1, x=2. These become the factors (x-1), (x-1), and (x-2). Then, by multiplying (x-1) and (x-1) you get x^2-2x+1. Multiply that by (x-2) to get your final answer, x^3-4x^2+5x-2.

16) Zeros are x=-1, x=5, and x=-2. You get the factors (x+1), (x-5), and (x+2). Multiply (x+1) and (x-5) to get x^2-4x-5. Multiply that by the other factor, (x+2), to get your final answer, x^3-2x^2-13x-10.

8 0

2 years ago

Let X represent the full height of a certain species of tree. Assume that X has a normal distribution with a mean of 137.1 ft an

Rama09 [41]

Answer:

0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.

0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 137.1, \sigma = 3.2$

A tree of this type grows in my backyard, and it stands 132.3 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.

This is the pvalue of Z when X = 132.3. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{132.3 - 137.1}{3.2}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.

My neighbor also has a tree of this type growing in her backyard, but hers stands 143.5 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.

This is 1 subtracted by the pvalue of Z when X = 143.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{143.5 - 137.1}{3.2}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.

7 0

3 years ago

25x^2+20x+4=0 solve by factoring pls show work (50points)

Inessa [10]

X= -2/5

SOLUTION
25x^2 + 20x + 4 = 0
(5x + 2)^2 = 0
5x + 2 = 0
x= -2/5

Hope this helps! :))

6 0

2 years ago