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3 years ago

Find the surface area of the equilateral triangular pyramid.

Mathematics

2 answers:

Tanzania [10]3 years ago

8 0

C is the correct answer

good luck

Helga [31]3 years ago

8 0

Answer:

i think the answer is C.

GOOD LUCK!!!

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If we had a Pyramid with a hexagonal base, how many of these pyramids would it take to fill up a hexagonal Prism with a congruen

klemol [59]

Idk what is the answers

5 0

2 years ago

Which one is right ?

sergey [27]

Answer:

6/10

Step-by-step explanation:

all can be reduced to 2/5, except 6/10:

2/5

8/20=2/5 (divide out 4)

12/30=2/5 (divide out 6)

but not

6/10 = 3/5!

7 0

2 years ago

The volume of a cuboid is 32cm^2 Two of the lengths are 4cm and 2cm, what is the missing length?

andrew-mc [135]

Answer:

4 cm

Step-by-step explanation:

to find the volume you multiply the lengths of all three sides together:

let 'm' = missing side

32 = 4·2·m

32 = 8m

m = 4

5 0

2 years ago

Read 2 more answers

Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.

Rudik [331]

The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section. That's
(change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.

4 0

2 years ago

University dean is interested in determining the proportion of students who receive some sort offinancial aid. rather than exami

vladimir2022 [97]

The confidence interval is
$0.59\pm0.081$

We first find p, our sample proportion. 118/200 = 0.59.

Next we find the z-score associated with this level of confidence:
Convert 98% to a decimal: 98% = 98/100 = 0.98
Subtract from 1: 1-0.98 = 0.02
Divide by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 2.33.

The margin of error (ME) is given by
$ME=z\sqrt{\frac{p(1-p)}{n}}
\\
\\=2.33\sqrt{\frac{0.59(1-0.59)}{200}}=2.33\sqrt{\frac{0.2419}{200}}\approx0.081$

This gives us the confidence interval
$0.59\pm0.081$

8 0

3 years ago