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nordsb [41]
3 years ago
9

Solve for equations -2yx+3x-2yx+3x

Mathematics
2 answers:
Scrat [10]3 years ago
6 0

Answer: − 4 y x + 6 x is the correct answer.

anyanavicka [17]3 years ago
4 0
-2x • (2y-3)

Explanation:
-x • (2y-3+2y-3)
-x • (4y-6)
-x • 2 (2y-3)
-2x • (2y-3)
You might be interested in
Is -0.3 a rational number? is 3.14144144414444... a rational number?
Ainat [17]

I will try to make this as simple as possible.

First off, we need to know what a rational number is: A rational number is any number that can be made by dividing 2 integers. For example:

1.5 would be a rational number because 1.5 = 3/2 (3 and 2 are both integers)

With that being said, let's begin.

First off, let's start with -0.3, let's ask ourselves, can we make this number by dividing 2 integers, the answer is yes, we can, by doing \frac{-3}{10} we have the equivalent of -0.3, so now we know it's a rational number.

As for the second one, it can't be a rational number because it can't be made by dividing to integers, so the answer is:

-0.3 is a rational number, but 3.14144144414444 is not.

Hope this helped! c:

3 0
3 years ago
Evaluate 11/6 - 2/8=
AleksandrR [38]

Answer:

19/12

Step-by-step explanation:

4 0
2 years ago
What is the inverse operation needed to isolate the variable 4 = p - 8
KatRina [158]
It’s addition

If you want I can explain it to you in the comments
4 0
3 years ago
Read 2 more answers
There are 5 times as many yellow labs as terriers in the dog park. if there are a total of 18 dogs, how many dogs are terriers?
gtnhenbr [62]
Terriers = x
Labs = 5x
5x + x = 18
6x = 18
6x / 6 = 18/6
x = 3
There are 3 Terriers
3 0
3 years ago
Read 2 more answers
Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=3, u'(0)= -4, v(0)= 2, v'(0)= -7. Find the value
3241004551 [841]
\bf \cfrac{d}{dx}[u(x)\cdot v(x)]\implies \cfrac{du}{dx}\cdot v(x)+u(x)\cdot \cfrac{dv}{dx}\quad 
\begin{cases}
u(0)=3\qquad u'(0)=-4
\\\\
v(0)=2\qquad v'(0)=-7
\end{cases}
\\\\
\left[ \cfrac{du}{dx} \right]_{x=0}\cdot v(0)+u(0)\cdot \left[ \cfrac{dv}{dx} \right]_{x=0}

so.. hmm pretty sure you know what that is
7 0
3 years ago
Read 2 more answers
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