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Artist 52 [7]
3 years ago
12

Which of the following shows the union of the sets? {4, 8, 12, 16, 20, 24, 28} {2, 4, 6, 8, 10, 12} A. {4, 8, 12} B. {4, 8, 12,

16} C. {6, 8, 10, 12} D. {2, 4, 6, 8, 10, 12, 16, 20, 24, 28}
Mathematics
1 answer:
kobusy [5.1K]3 years ago
6 0

<h2> <em>D.{2, 4, 6, 8, 10, 12, 16, 20, 24, 28}</em></h2><h2 /><h2 />
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Use the graph of the function g to answer the following. use correct formatting for your work
netineya [11]

9514 1404 393

Answer:

  • f(-2) = 4
  • f(1) = -5
  • D: [-3, ∞)
  • R: [-5,  11]

Step-by-step explanation:

You have marked the points on the graph corresponding to ...

  f(-2) = 4

  f(1) = -5

__

The domain is the horizontal extent, from x = -3 to +∞.

The range is the vertical extent, from y = -5 to +11 (inclusive).

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3 years ago
If two matrices, A and B, are equal, which of the
alexandr402 [8]

If A and B are equal:

Matrix A must be a diagonal matrix: FALSE.

We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:

A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]

Both matrices must be square: FALSE.

We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works

Both matrices must be the same size: TRUE

If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.

For any value of i, j; aij = bij: TRUE

Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.

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3 years ago
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What are the solutions of x^2-4x+5=0
Gnoma [55]

Answer:

Factor {x}^{2}-4x-5x

​2

​​ −4x−5.

(x-5)(x+1)=0(x−5)(x+1)=0

2 Solve for x.

x=5,-1x=5,−1

Step-by-step explanation:

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3 years ago
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What is 3 3/8 +3 1/2 using common denominator
horrorfan [7]
1/2=4/8. 3 and 4/8+ 3 and 3/8 is 6 and 7/8.
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3 years ago
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Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

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