9514 1404 393
Answer:
- f(-2) = 4
- f(1) = -5
- D: [-3, ∞)
- R: [-5, 11]
Step-by-step explanation:
You have marked the points on the graph corresponding to ...
f(-2) = 4
f(1) = -5
__
The domain is the horizontal extent, from x = -3 to +∞.
The range is the vertical extent, from y = -5 to +11 (inclusive).
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer:
Factor {x}^{2}-4x-5x
2
−4x−5.
(x-5)(x+1)=0(x−5)(x+1)=0
2 Solve for x.
x=5,-1x=5,−1
Step-by-step explanation:
1/2=4/8. 3 and 4/8+ 3 and 3/8 is 6 and 7/8.

We want to find
such that
. This means



Integrating both sides of the latter equation with respect to
tells us

and differentiating with respect to
gives

Integrating both sides with respect to
gives

Then

and differentiating both sides with respect to
gives

So the scalar potential function is

By the fundamental theorem of calculus, the work done by
along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it
) in part (a) is

and
does the same amount of work over both of the other paths.
In part (b), I don't know what is meant by "df/dt for F"...
In part (c), you're asked to find the work over the 2 parts (call them
and
) of the given path. Using the fundamental theorem makes this trivial:

