1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Inga [223]
3 years ago
5

The area of a rectangular garden is 5828 m

Mathematics
2 answers:
evablogger [386]3 years ago
6 0

Answer:

The length of the garden is 94 m.

Step-by-step explanation:

you do 5828 m. divided by 62m. and that is how you get your answer of 94 m.

malfutka [58]3 years ago
6 0

Answer:

94

Step-by-step explanation:

Area of a rectangle = Length x Width

5828 = L x 62

Length = 5828/62

Length = 94

You might be interested in
A=8, b=5, C=90 degree; Find c, A, and B<br><br> This is for the law of sine and cosine
brilliants [131]

Answer:

• c = √89 ≈ 9.434

• A = arcsin(8/√89) ≈ 57.995°

• B = arcsin(5/√89) ≈ 32.005°

Step-by-step explanation:

By the law of cosines, ...

c² = a² + b² -2ab·cos(C)

Since c=90°, cos(C) = 0 and this reduces to the Pythagorean theorem for this right triangle.

c = √(8² +5²) = √89 ≈ 9.434

Then by the law of sines (or the definition of the sine of an angle), ...

sin(A) = a/c·sin(C) = a/c = 8/√89

A = arcsin(8/√89) ≈ 57.995°

sin(B) = b/c·sin(C) = b/c = 5/√89

B = arcsin(5/√89) ≈ 32.005°

6 0
3 years ago
Hshehebeirjiejeueb why
Aleksandr [31]

Answer:

chinese?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help I need it ASAP
Anastasy [175]

Answer:

-83/51

Step-by-step explanation:

i used an app called Symbolab that solves any math problem for u

3 0
3 years ago
Suppose that many large samples are taken from a population and that the
rewona [7]

Answer:

0.22 -1 *0.029 =0.191

0.22 +1 *0.029 =0.249

And the best option would be:

D. (0.191 to 0.249)

Step-by-step explanation:

For this case we know that the mean is:

\bar X = 0.22

And the standard error is given by:

SE = 0.029

We want to construct a 68% confidence interval so then the significance level would be :

\alpha=1-0.68 = 0.32 and \alpha/2 =0.16. The confidence interval is given by:

\bar X \pm z_{\alpha/2} SE

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

z_{\alpha/2}= 1

And replacing we got:

0.22 -1 *0.029 =0.191

0.22 +1 *0.029 =0.249

And the best option would be:

D. (0.191 to 0.249)

5 0
3 years ago
Can somebody please help me with this question
aleksandr82 [10.1K]

Answer:

An event can have a probability of 3/2  is not true

Step-by-step explanation:

The probability of an event happening is between 0 and 1 inclusive.

A probability of 1 means the event is certain to happen or 100%

You cannot have a probability greater than 1 so

An event can have a probability of 3/2 cannot happen

4 0
3 years ago
Other questions:
  • Please answer the question in the screen shot right
    13·2 answers
  • -9+5 What is the answer of this question? It is Integers
    12·2 answers
  • The diameter of a sphere is 4 cm which represents the volume of the sphere?
    13·2 answers
  • identify all the pionts that would lie on the line y=1/3x + 9. answer choices A: 0,9 B: -9,6 C: 3,10 D: 12,-5
    7·1 answer
  • PLEASE HELP ASAP (8th grade question)
    15·1 answer
  • The figure shows an equilateral triangle with its sides as indicated. find the length of each side of the triangle .
    11·1 answer
  • HELP!! I WILL MARK U BRAINLIEST IT DUE IN 10 MINSSS
    7·1 answer
  • There are 4 cups of flour in 3 batches of cookies . How many cups are in one batche.
    9·2 answers
  • Compound interest of $1000 is invested at 10% compounded continuously, the future value s at any time t in years is given by s=1
    13·1 answer
  • Joe has $150 in his saving account and saves $40 per month. Which equation represents the amount Joe has in his account after x
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!