Answer:
The mean is 80 and the standard deviation is 20. Therefore we have
65 is 0.75 standard deviation below the mean.
Step-by-step explanation:
z = 
Since 85 is 0.25 standard deviations above the mean we have
or 0.25·σ = 85 - μ......1
1.5 = 
or 1.5·σ = μ - 50..............2
From 1 we have σ = 340 - 4·μ substituting into 2 gives
1.5·(340 - 4·μ) = μ - 50 ⇒ 510 - 6·μ = μ - 50
7·μ = 560 or μ = 80
Therefore σ = 340 - 4·μ = 340 - 4·80 = 20
A value, x, 0.75 standard deviation below the mean is given by
0.75 = 
which gives 15 = 80 - x or
x = 65.
Answer: The number of solutions to the given equation is zero.
Step-by-step explanation: We are given to find the number of solutions to the following equation :
To find the number of solutions, we must solve the given equation.
The solution of equation (i) is as follows :
which can never be possible.
So, the given equation has no solution.
Thus, the number of solutions to the given equation is zero.
Answer:
nonlinear
Step-by-step explanation:
Answer:
Step-by-step explanation:
The ys have to have the same value. That allows you to equate the right side of each y to each other.
-x^2 + 4 = 2x + 1 Subtract the right side from the left side.
-x^2 + 4 - 2x - 1 = 2x-2x +1 - 1 Combine
-x^2 - 2x + 3 = 0 Multiply both sides by - 1
-1(-x^2 - 2x + 3) = 0*-1 Remove the brackets
x^2 + 2x - 3 Factor
(x - 1)(x + 3 )
x - 1 = 0
x = 1
x + 3 = 0
x = - 3
So the line goes through x = 1 or x = - 3
x = 1
y = 2x + 1
y = 2(1) + 1
y = 3
x = - 3
y = 2(-3) + 1
y = - 6 + 1
y = - 5
Does the graph confirm this? See below.
red: y = -x^2 + 4
green: y = 2x + 1
Yes the graph is in agreement.
Answer:
25x + 15800
Step-by-step explanation:
Given
The amount of money in both banks over time represented by the functions;
f ( x ) = 50 x + 6500 and g( x ) = − 25 x + 9300
The total amount of money in the two accounts over time is expressed as;
h(x)= f(x) + g(x)
Substitute;
h(x) = 50 x + 6500 + (− 25 x + 9300)
h(x) = 50x - 25x +6500+9300
h(x) =25x + 15800
Hence the sum of the money in the account over time is 25x + 15800
