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Anastaziya [24]
3 years ago
11

Pls help

Mathematics
1 answer:
denpristay [2]3 years ago
5 0
The cost of the bond was 90/100 times $5,000, that is, $4,500 total. 

<span>The annual interest is 5% of $5,000, that is, $250. </span>

<span>The current yield is 5% divided by (90/100), that is 5.555%; round to 5.6% as instructed. </span>

<span>The yield that real bond buyers would be more interested in is the yield to maturity, but this cannot be calculated without knowing the term (number of years). If it's a short term bond that will pay you back $5,000 in just a few years, that would add several percent to the yield, but if it's a 15-year bond the growth of the $4,500 to $5,000 adds only a fraction of 1% to the yield.</span>
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If you help me I'll make as brilliant​
MissTica

The answer is A) 3/100.

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The sum of a number and its ____________ is zero.
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Negative counterpart

5 + -5 = 0
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7 is added to 1/2 of h
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Answer:

14+h

Step-by-step explanation:

7 + 1/2 × h

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Let $\angle D$ be an acute angle such that $\tan D=0.72$ . Use a calculator to approximate the measure of $\angle D$ to the near
pentagon [3]

Answer:

D = 35.8 degrees

Step-by-step explanation:

In this question, we are asked to use calculator to estimate the approximate measure of angle D given its tan value.

From the question, what we have is;

tan D = 0.72

Now to calculate the acute angle D, we will divide through by tan

hence,

D = tan^-1 0.72

or more simply tan^-1 can be called arc tan

Thus, D = arc tan 0.72

D = 35.75

D = 35.8 to the nearest tenth of a degree

4 0
3 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
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Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
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