Answer:
A
Step-by-step explanation:
law of sine
c/sin(C) = b/sin(B) = a/sin(A)
with the sides and corresponding angles being always opposite.
sin(90) = 1
sin(30) = 0.5
c, the Hypotenuse, is the longest side in such a right-angled triangle.
c/1 = b/0.5
b = c×0.5 = c/2
so, one side has to be half the length of the longest side (Hypotenuse).
the only answer meeting that criteria is A.
the longest side is 10×sqrt(3) = 17.32...
the side half of that is 5×sqrt(3).
and Pythagoras for such a triangle is then
c² = (c/2)² + a²
c² = c²/4 + a²
so, a² = 3c²/4
c² = c²/4 + 3c²/4
therefore we can check also the third side
15² = 3×(5×sqrt(3))² = 3×25×3 = 3×75 = 225 = 15²
correct.
A is such a triangle.
24987.2 meters cubed.
Step-by-step explanation:
A Hemisphere is 1/2 of a sphere, so let's find the volume of a sphere and then cut it in half.
The volume of a sphere is V= (4/3)πr3
The diameter is double the size of the radius, so we can find r, the radius, by dividing the diameter,
45.7m, by 2. So r = 22.85 meters
so the volume of the sphere is (4/3)π(22.85 meters)3, which is 49974.35787 meters cubed.
Since we're actually looking for the Hemisphere, we can divide this volume in half to get the volume of the hemisphere as 24987.17894 meters cubed.
And because the answer must be to 1/10th of a cubic meter, that means we only want one decimal point. So we round to 24987.2 meters cubed.
Answer:2 and 7
Step-by-step explanation:
I hope it's right :)
Answer:
A)$ 45
B) $105
Step-by-step explanation:
Bag and a belt cost $255
Let bag = x
Let belt = y
X+y= 255 equation 1
Let total money be z first
Remaining money= z-255
X-30 = z-255
Y +15 = z-255
Equating the left side of the equation
X+30 = y+15
X-y= 45 equation 2
Solving simultaneously
X+y= 255
X-y= 45
2x = 300
X= 150
If x= 150
150-y= 45
150-45= y
105=y
Bag = $150
Belt = $105
Bag Is 150-105 more than the belt
150-105= $45
Answer:
17 teaspoons
Step-by-step explanation:
1 tbs : 3 tsp
Always start by converting mixed numbers into fractions;
multiply the whole number part by the denominator (under part) of the fraction part and add this to the numerator (upper part);
Then simply apply the ratio.
