Answer:
Cartesian
z₁= 3 +4*j
z₂= 2 +3*j
Polar
z₁=5 * e^ (0.927*j)
z₁=√13 * e^ (0.982*j)
Step-by-step explanation:
for the complex numbers z the cartesian form of is
z= x + y*j
then
1) z₁= 3 +4*j (cartesian form)
2) z₂= 2 +3*j (cartesian form)
the polar form is
z= r* e^jθ
where
r= √(x²+y²) → r₁ = √(3²+4²) = 5 , r₂ = √(2²+3²) = √13
and
θ = tan⁻¹ (y/x) → θ₁ = tan⁻¹ (4/3)= 0.927 rad , θ₂ = tan⁻¹ (3/2)= 0.982 rad
then
z₁=5 * e^ (0.927*j)
z₁=√13 * e^ (0.982*j)
6 less than 2 and a number.
No.
The correct choice is ...
A. (3, 2)
Answer:
y-3 = -4 (x-1)
Step-by-step explanation:
y= -4x - 5
In slope-intercept form, they give us the slope, -4, and the y-intercept, -5 (we don't need for point-slope form).
Use the point (1,3) and substitute it into the equation.
Point-slope form: y-y1 = m(x-x1)
y-3 = -4 (x-1)
Point slope form
y<span> – </span>y1<span> = </span>m(x<span> – </span>x1<span>)
</span>
so equation
y + 5 = 5/7(x - 8)
hope that helps
