If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.
A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;
Z = x - μ / σ
In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.
The p-value can be used to determine the z-score with the help of a standard table.
As we have to find the minimum score to be in the top 2%, p-value = 0.02
The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054
Therefore,
2.054 = x - 76.4 ÷ 6.1
2.054 × 6.1 = x - 76.4
12.529 = x - 76.4
12.529 + 76.4 = x
x = 88.929
Hence 88.929 is calculated to be the lowest score required to be in the top 2%.
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Answer:
The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)
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Step-by-step explanation:
Given


Required
Find all zeros of the f(x)
If
then:

And
is a factor
Divide f(x) by x - 8

Expand the numerator

Rewrite as:

Factorize

Expand

Factorize


Multiply both sides by x - 8

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>
Answer:
Option D - 60
Step-by-step explanation:
Given : Connor made 9 shapes with straws. Each shape had 5 straws. Conor used 15 more straws to make more shapes.
To find : What is the total number of straws Connor used to make all the shapes?
Solution :
To make 1 shape Connor required 5 straws.
To make 9 shape connor required
straws.
Now, there were 45 straws.
Conor used 15 more straws to make more shapes.
The total number of straws Connor used to make all the shapes are
Therefore, Option D is correct.
Cannor used 60 straws to make shapes.
You first work out the mean then for each number subtract the mean and square the result then work out the mean of those squared differences and take the square rot of that and you're done :)