Question

A mixture of oxygen, hydrogen, and nitrogen exerts a total pressure of 378 kPa. If the partial pressures of oxygen and hydrogen are 212 kPa and 101 kPa respectively, find the partial pressure exerted by nitrogen.
A. 65 kpa
B. 313 kpa
C. 166 kpa
D. 277 kpa

Answer 1

Answer:

The correct answer is option A.

Explanation:

Total pressure of  mixture = p = 378 kPa

Partial pressure of the oxygen gas = $p^o_{O_2}=212 kPa$

Partial pressure of the hydrogen gas = $p^o_{H_2}=101 kPa$

Partial pressure of the nitrogen gas = $p^o_{N_2}=?$

As we know that total pressure is sum of partial pressures exerted by all the individual gases.

$p=p^o_{O_2}+p^o_{H_2}+p^o_{N_2}$

$378 kpa=212 kPa+101 kPa+p^o_{N_2}$

$p^o_{N_2}=378 kPa - 212 kPa-101 kPa=65 kPa$

65 kPa the partial pressure exerted by nitrogen.

Answer 2

As we know that

P total = pO +pH +pN

so

P = P1 + P2 + P3

378 kPa= 212 kPa + 101 kPa + P(H2)

P(H2) = 65 kPa

partial pressure is 65

so correct option is A 

hope it helps