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lisabon 2012 [21]
2 years ago
5

Help me please!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Usimov [2.4K]2 years ago
8 0

Answer:

69

Step-by-step explanation:

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Quick algebra 1 question for 50 points!
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The line is parallel to y axis

We know that if a line is parallel to y axis

  • slope=tan90=undefined

So there is no slope

Here it has constant x value as -2

So the equation is

  • x=-2

Option A

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2 years ago
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Suppose that $2000 is invested at a rate of 2.6% , compounded semiannually. Assuming that no withdrawals are made, find the tota
EleoNora [17]

Answer:

$2,589.52

Step-by-step explanation:

A = P(1 + \dfrac{r}{n})^{nt}

We start with the compound interest formula above, where

A = future value

P = principal amount invested

r = annual rate of interest written as a decimal

n = number of times interest is compound per year

t = number of years

For this problem, we have

P = 2000

r = 0.026

n = 2

t = 10,

and we find A.

A = $2000(1 + \dfrac{0.026}{2})^{2 \times 10}

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3 years ago
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Write and solve a story problem for each method you can use to find decimal sums and differences.
Pavlova-9 [17]

Answer:

could you give me some story problems Plz

Step-by-step explanation:

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3 years ago
What are two other names for Xy
NARA [144]

Answer:

In Mathematics, x and y are examples of variables.

You can use any letter as a variable but, make sure to include a let statement when using variables.

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Hope this helps!

Step-by-step explanation:

3 0
3 years ago
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Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

8 0
3 years ago
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