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nydimaria [60]
2 years ago
9

Is 6 a factor for 71

Mathematics
1 answer:
bekas [8.4K]2 years ago
6 0

Answer:

no its not kpfkansnsbsdhdbdb

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Consider the following frequency distribution.
Zarrin [17]

Answer:

Class interval                            10-19 20-29 30-39 40-49 50-59

cumulative frequency               10      24       41        48       50

cumulative relative frequency 0.2   0.48     0.82    0.96      1

Step-by-step explanation:

1.

We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.

Cumulative frequency

10

10+14=24

14+17=41

41+7=48

48+2=50

sum of frequencies is 50 so the relative frequency is f/50.

Relative frequency

10/50=0.2

14/50=0.28

17/50=0.34

7/50=0.14

2/50=0.04

Cumulative relative frequency

0.2

0.2+0.28=0.48

0.48+0.34=0.82

0.82+0.14=0.96

0.96+0.04=1

The cumulative relative frequency is calculated using relative frequency.

Relative frequency is calculated by dividing the respective frequency to the sum of frequency.

The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.

The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.

4 0
3 years ago
Find the remainder when x51+x is divided by x+1
kaheart [24]

Answer:

-2

Step-by-step explanation:

By definition, the remainder is the portion of the dividend that is not evenly divisible by the divisor. Basically, it is what's left over. In this case, -2 is the amount left over after dividing this equation.

3 0
3 years ago
300x+290 factor out the gfe of each expression
marta [7]

Answer: 590x.

2 is GFE, hope this helps?

Step-by-step explanation:

3 0
2 years ago
CAN SOMEONE PLEASE HELP I NEED THESE LAST TWO I NEED TO TURN IT IN
kirza4 [7]

Answer: a. Area b. 4222.26

6 0
2 years ago
Alice's grandfather is showing Alice his apple
Amanda [17]

There are  156 rows of trees altogether.

<u>Step-by-step explanation:</u>

Given that for every 11 rows of Red delicious , they plant 3 rows of Royal Gala.

Thus for 1 row of Royal Gala there would be 11/3 rows of Red delicious.

Number of rows of Royal Gala=18

corresponding\ number\ of\ Red\ delicious\ = 11/3 \times 18=11\times 6=66

For 11 rows of red delicious,they plant 7 rows of yellow delicious.

Thus for 1 row of Red delicious,there would be 7/11 rows of yellow delicious.

For 66 rows of red delicious there would be

7/11\times66=7\times 6=42 rows\ of\ yellow\ delicious

For 11 rows of red delicious,they plant 5 rows of Braeburn

for 1 row of red delicious,they would plant 5/11 rows of Braeburn.

For 11 rows of red delicious,they would plant

5/11\times 66=5\times 6=30\ rows\ of\ braeburn

Total rows of trees=66+42+30+18=156

8 0
3 years ago
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