Answer:
It is not a one to one function
Step-by-step explanation:
Required
Determine if f(x) = round(x) is a one to one function
This question is best answered using illustrating values;
Let x = 1.1
f(x) = round(x) becomes
f(1.1) = round(1.1)
f(1.1) = 1
Let x = 1.3
f(x) = round(x) becomes
f(1.3) = round(1.3)
f(1.3) = 1
Notice that for the two values of x, f(x) has the same value of 1.
This two illustrating values can be used to conclude that the fuction is not one-to-one.
Answer:
D. either x or y must equal 0
Step-by-step explanation:
Its given that xy = 0
Remember that product of two numbers can be zero only if:
Both of them are zero or Either of them is zero as zero multiplied to any non-zero number will always be equal to zero. This is known as Zero Product Property.
So, if the product of x and y is equal to 0 there are two possibilities:
- Both x and y are equal to 0
- Either x or y must be equal to 0
Note that the condition both x and y are equal to zero is not a must condition, because even if one of them is equal to zero, the entire expression will be equal to zero.
Hence, the condition which has to be true in all cases for xy = 0 is:
D. either x or y must equal 0
The answer is B because 40 is under hours of training and 1400 is under monthly pay
The correct answer is; 14x +4
Factors of 84: 1, 2<span>, </span>3<span>, 4, 6, </span>7<span>, 12, </span>14<span>, </span>21<span>, </span>28<span>, </span>42<span>, 84. Prime factorization: 84 = </span>2<span> x </span>2<span> x </span>3<span>x </span>7<span> which can also be written (</span>2^2<span>) x </span>3<span> x </span>7<span>.</span>
