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svetoff [14.1K]
3 years ago
6

Simplify- 5+2{3x+7(2-x)}

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

16x+19

Step-by-step explanation:

i might be wrong and its gonna take so long to explain it

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Farrah's goal is to use 236 gallons of water or less per day at her business. Her water bill showed that 8262 gallons were used
Vikki [24]

Answer: No

Step-by-step explanation:

8262 divided by 35 equals 236.05 something something something. So that is more than 236. Close, but no.

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What is the equation of a line, in general form, with a slope of -2 and a y-intercept of 8?
n200080 [17]

2x+y-8=0.

8 0
3 years ago
Find the third quartile Q3 of the list of 24 sorted values shown below.
emmainna [20.7K]

Answer:

60

Step-by-step explanation:

The computation of the third quartile is given below:

The third quartile Q3 is

= 3(n + 1)÷ 4

= 3 (24 + 1) ÷ 4

= 75 ÷ 4

= 18.75th term

Now the 18.75th term is

= 18th term + 0.75 term

= 57 +  (19 term - 18term)

= 57 +  0.75 (61 - 57)

= 57 + 0.75 (4)

= 60

8 0
3 years ago
Suppose that the speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles p
denis23 [38]

Answer:

A)X \sim N(68 , 25)

B) the probability that is traveling more than 70 mph is 0.3446

C) the probability that it is traveling between 65 and 75 mph is 0.6449

D) 90% of all cars travel at least 56.85 mph fast on the freeway

Step-by-step explanation:

The speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles per hour.

Mean = \mu = 68 mph

Standard deviation = \sigma = 5 mph

A) X ~ N( _____, _______ )

In general X \sim N( \mu , \sigma^2)

\mu = 68 mph

\sigma = 5 mph

\sigma^2 = 5^2 = 25

So, X \sim N(68 , 25)

B) If one car is randomly chosen, find the probability that is traveling more than 70 mph.i.e.P(X>70)

So,Z = \frac{x-\mu}{\sigma}\\Z=\frac{70-68}{5}

Z=0.4

Using Z table

P(Z>70)=1-P(Z<70)=1-0.6554=0.3446

Hence the probability that is traveling more than 70 mph is 0.3446

C) If one of the cars is randomly chosen, find the probability that it is traveling between 65 and 75 mph.

P(65<X<75)

Z = \frac{x-\mu}{\sigma}

AT x = 65

Z=\frac{65-68}{5}

Z=-0.6

AT x = 75

Z=\frac{75-68}{5}

Z=1.4

Using Z table

P(65<X<75)=P(-0.6<Z<1.4)=P(Z<1.4)-P(Z<-0.6)=0.9192-0.2743=0.6449

Hence the probability that it is traveling between 65 and 75 mph is 0.6449

D)90% of all cars travel at least how fast on the freeway?

Since we are supposed to find at least how fast on the freeway

So,P(X>x)=0.9

1-P(X<x)=0.9

1-0.9=P(X<x)

0.1=P(X<x)

Z value at 10% =-2.23

So, Z=\frac{x-\mu}{\sigma}\\-2.23=\frac{x-68}{5}\\-2.23 \times 5 =x-68\\(-2.23 \times 5)+68=x

56.85 = x

Hence 90% of all cars travel at least 56.85 mph fast on the freeway

8 0
3 years ago
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