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ankoles [38]
3 years ago
10

I WILL MARK YOU AS BRAINLIEST IF YOU ANSWER THIS!!!! PLEASE ITS FOR A TEST!!!

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Factoring a binomial

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The price of a train ticket from Orlando to Atlanta is normally $118.00. However, the train company is offering a special 75% di
pogonyaev

Answer:

$88.50

Step-by-step explanation:

118*0.75 = 88.50

8 0
3 years ago
Kathy needs money for a trip to Europe if she has US$300 in the bank but wants to withdraw half of it In British pounds and half
Aleks [24]

Answer: She has 21.63 more euros than pounds and has 1.23 times more euros than pounds.

Step-by-step explanation:

She has US$300, and she will withdraw half of it on pounds, and half of it in euros.

(half of US$300 is US$150)

We know that:

1 pound = US$1.6

(1 pound/US$1.6) = 1

Then US$150 = US$150*(1 pound/US$1.6) = (150/1.6) pounds = 93.75 pounds.

And we also know that:

1 euro = US$ 1.3

then:

(1 euro/US$ 1.3) = 1

This means that:

US$150 = US$150*(1 euro/US$ 1.3) = (150/1.3) euros = 115.38 euros.

This means that:

115.38 - 93.75 = 21.63

This means that she has 21.63 more euros than pounds.

and:

115.38/93.75 = 1.23

She has 1.23 times more euros than pounds.

6 0
3 years ago
5. A function is given below.<br> f(x) = 3x2 - x + 6<br> What is f(2)?<br> 2
goldenfox [79]

Answer:   10

Step-by-step explanation:

f(x)= 3 (2) - x + 6

f(x)= 6 - 2 + 6

f(x)=  4 + 6

f(x) = 10

7 0
3 years ago
Read 2 more answers
Is 0/0x7y³ a positive or negative number
charle [14.2K]

Answer:

A =  0/(0 x 7y³)

Let's see the denominator:  0 x 7y³ = 0

=> Whenever the denominator is 0, A is undefined, neither a positive number or negative number

Hope this helps!

:)

3 0
3 years ago
(x+5)(√ 1-x)<br> what is the product of this composite function?
Radda [10]

Answer:

x\sqrt{1-x}+5\sqrt{1-x}

Step-by-step explanation:

(x+5)(\sqrt{1-x} )\\\\=\left(\sqrt{1-x}\right)\left(x+5\right)\\\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\\\a=\left(\sqrt{1-x}\right),\:b=x,\:c=5\\\\=\left(\sqrt{1-x}\right)x+\left(\sqrt{1-x}\right)\times\:5\\\\=x\left(\sqrt{1-x}\right)+5\left(\sqrt{1-x}\right)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\=x\sqrt{1-x}+5\sqrt{1-x}

6 0
3 years ago
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