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3 years ago

Which of the following CANNOT be given the lengths of the sides of a triangle?

2 answers:

6 0

The sides of a triangle must satisfy the triangle inequality, which states the sum of the lengths of any two sides is strictly greater than the length of the remaining side.

We really only have to check if the sum of the two smaller sides exceeds the largest side.

A. 5+6>7, ok

B. 6+6>10, ok

C. 7+7=14 Not ok, this is a degenerate triangle not a real triangle

D. 4+6>8 ok

Answer: C

nekit [7.7K]3 years ago

5 0

The answer is option C.

To construct a Triangle..

One of the criterion is Sum of two sides must be More than The third side.

In Option C. " 7+7=14 " This Series can only form line segment and not a triangle.

Hope it helps...

Regards;

Leukonov/Olegion.

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What is the slope of a line that passes through (–4,–13) and (19,11)?

Anna11 [10]

For points (x1,y1) and (x2,y2)
slope=(y1-y2)/(x1-x2)

(-4,-13)
(19,11)
x1=-4
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x2=19
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3 years ago

Read 2 more answers

Simplify. Write your answer using whole numbers and variables.

Andre45 [30]

Answer:

q + 7

Step-by-step explanation:

(q² + 4q − 21) / (q − 3)

Factor the numerator:

(q + 7) (q − 3) / (q − 3)

Divide:

q + 7

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3 years ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

3 years ago

What is x minus the square root of 2

Zielflug [23.3K]

Answer:

x - sqrt(2)

Step-by-step explanation:

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2 years ago

How do I solve this?

Yuki888 [10]

The answer is B. The values of y must only be positive because it is equal to
$| - x|$
The other options states that the values of y could be negative which is why it is wrong.

3 0

3 years ago