PLEASE HELP ME WITH THIS!! ILL GIVE BRAINLIEST

A 2 liter bottle of coke for $1.39 or a 12 pack of 12 ounce cams of pepsi for $3.49? which is the best deal

pav-90 [236]

A 2-liter bottle of Coke for $1.39 is the best deal. No need to divide.

5 0

3 years ago

Read 2 more answers

Help 20 ptssss asap !

ELEN [110]

Answer:

Assuming you want an equation, y = -4/3x - 1

Step-by-step explanation:

Formula is y = mx + b

m = slope= -4/3

b = y-intercept = -1

4 0

3 years ago

Given: AB = BC Prove: B is the midpoint of AC. A line contains point A, B, C. A flow chart has 3 boxes that go from top to botto

aliina [53]

Answer:

flowchart proof

Step-by-step explanation:

3 0

3 years ago

What goes into 9 12 6 3 and 4

Leokris [45]

It could possibly be one.

3 0

3 years ago

The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h

saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

$P(X=4)=\frac{\lambda^{X}*e^{-\lambda} }{X!} =\frac{5^{4}*e^{-5} }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754$

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))$

Using

$P(X)=\frac{\lambda^{X}*e^{-\lambda} }{X!}$

We get

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\$

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

$EV=\lambda*t=5*0.75=3.75$

8 0

3 years ago