Question

I don’t remember learning this so help would be greatly appreciated

Answer 1

$\bf sin^2(\theta )=\cfrac{3}{4}\implies [sin(\theta )]^2=\cfrac{3}{4}\implies \sqrt{[sin(\theta )]^2}=\sqrt{\cfrac{3}{4}}\implies sin(\theta )=\cfrac{\sqrt{3}}{\sqrt{4}} \\\\\\ sin(\theta )=\cfrac{\sqrt{3}}{2}\qquad \qquad \stackrel{\textit{and if you check on your handy dandy \underline{Unit Circle}}}{\theta =\cfrac{\pi }{3}~~~~\textit{on I Quadrant},\qquad \theta =\cfrac{2\pi }{3}~~~~\textit{on II Quadrant}}$