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Elodia [21]
3 years ago
5

120 is 15% of what number

Mathematics
2 answers:
son4ous [18]3 years ago
6 0
120 = 15% x

15% = 0.15

x = 120 / 0.15 = 800
choli [55]3 years ago
5 0
Its .15 because you multiply then divide by 100
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Graph the relation shown in the table. Is the relation a function? Why or why not?
patriot [66]

Answer:

The chosen topic is not meant for use with this type of problem. Try the examples below.

x + 6 y = 5

6 x + 2 y = 8

x − y + 4 = 8

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2 .

x y =

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0 − 4 = − 4

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Step-by-step explanation:

Find the equation with a point and y-intercept.

y = ( y/ x  −  y )  x  +  x y

The chosen topic is not meant for use with this type of problem. Try the examples below.

( 0 , 9 )  ,  ( 8 , 6 )

( 0 , 9 )  ,  ( 5 , 4 )  ,  ( 1 , 4 )

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4 0
3 years ago
Please answer this multiple choice question correctly for 30 points and brainliest!!
Softa [21]

Answer:

  B.  88°

Step-by-step explanation:

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  (122/500)×360° = 87.84° ≈ 88°

7 0
3 years ago
There are 12 months in a year.
erica [24]

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(click choose and pin the photo please) so that i can see options

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3 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

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From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

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\dfrac{1}{3}(m-4)=8-4

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m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
3 years ago
Perform the indicated operation.<br><br> 14 - (-10)
Rashid [163]
The answer for that is 24.
3 0
3 years ago
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