Answer:
Red line
Step-by-step explanation:
2y+x=0
2y=-x
y=-x/2
Put the equation into y=mx+b so you would need to subtract the x to put it on the right side so then you’ll have 2y=-x+0 then divide by 2 to get the y by itself then you’ll have y=-2x+0 that means the line would be negative and the y-intercept is 0 and the only line that follows that is the red line.
4 - (x+2) < -3(x+4)
4 -1(x) -1(2) < -3(x) -3(4)
4 - x - 2 < -3x -12
<u> +3x +3x </u>
<u />2 + 2x < -12
<u>-2 -2
</u> 2x < -14
<u /> <u> ÷2 ÷2 </u>
x < -7
assume that x = -8
4 - (-8 + 2) < -3(-8 + 4)
4 - (-6) < -3(-4)
4 + 6 < 12
10 < 12 the inequality is true.
Answer:
I think it is a and f i could be wrong
Step-by-step explanation:
The limit is presented in the following undefined form:

In cases like this, we can use de l'Hospital rule, which states that this limit, if it exists, is the same as the limit of the derivatives of numerator and denominator.
So, we switch

The derivative of the numerator is

Whereas the derivative of the denominator is

So, the new limit is

So, it would seem that we didn't solve anything, but indeed we have! Recall the limit

to conclude that the limit converges to \dfrac{6}{25} [/tex]