u = 10.4 and v = 12
Solution:
In the given 2 sides of a triangle are 60°, 60°.
Sum of all the angles of a triangle = 180°
60° + 60° + third angle = 180°
⇒ third angle = 180° – 60° – 60°
⇒ third angle = 60°
All angles are equal, therefore the given triangle is an equilateral triangle.
⇒ All sides are equal in length.
⇒ v = 12
The line drawn from the top angle divides the triangle into two equal parts
and the line is perpendicular.
12 ÷ 2 = 6
Using Pythagoras theorem,

⇒ 
⇒ 
⇒ 
⇒ 
⇒ u = 10.4
Hence, u = 10.4 and v = 12.
Answer
1 + 32 + 243 + 1024 + .. + n5
Step-by-step explanation:
Answer:
42 ft, 60 ft, 84 ft
Step-by-step explanation:
let x be the shortest side , then the other 2 sides are 2x and x + 18, so
x + 2x + x + 18 = 186 , that is
4x + 18 = 186 ( subtract 18 from both sides )
4x = 168 ( divide both sides by 4 )
x = 42
Then lengths of sides are
x = 42 ft
2x = 2 × 42 = 84 ft
x + 18 = 42 + 18 = 60 ft
Answer:
Given the size of rectangular plate in advertisement = 5 cm by 3cm.
Given the condition for length should be = 0.25 of 5 cm
Step-by-step explanation:
Now, have to write the inequality from the given data.
Therefore, 5- 0.25 ≤ L ≤ 5+.25
4.75 ≤ L ≤ 5.25
We know that the area of a rectangle = Length × Width.
Width = 3
Thus, the area is 3 × L
3× (4.75) ≤ 3×L ≤3× (5.25)
14.25 ≤ 3×L ≤ 15.75
So the minimum area is 14.25 cm^2
The maximum area is 15.75 cm^2
Consecutive odd integers are 2 apart
they are x and x+2
the product (x times (x+2)) is 1 less than 4 times their sum
x(x+2)=-1+4(x+x+2)


![x^2+2x=8x+7 minus (8x+7) from both sides [tex]x^2-6x-7=0](https://tex.z-dn.net/?f=x%5E2%2B2x%3D8x%2B7%20minus%20%288x%2B7%29%20from%20both%20sides%20%5Btex%5Dx%5E2-6x-7%3D0)
factor
what numbers multliply to get -7 and add to get -6?
-7 and 1
(x-7)(x+1)=0
set equal to 0
x-7=0
x=7
x+1=0
x=-1
so the x can be 7 or -1
the other number (x+2) can be 7 or 1
test each
7 and 9
7(9)=-1+4(7+9)
63=-1+4(16)
63=-1+64
63=63
true
-1 and 1
-1(1)=-1+4(-1+1)
-1=-1+4(0)
-1=-1+0
-1=-1
true
the 2 integers can be 7 and 9 or -1 and 1 (both pairs of numbers work)