The best answer I believe is t - 2
The expression y = y + 8 does neither represent an odd number nor an even number.
<h3>Does represent a given equation an even or odd number or neither?</h3>
In this problem we must check if a given algebraic equation represents an even number or an odd number or neither by using algebraic means. Even numbers are integers, whose last digit is 0, 2, 4, 6 or 8, whereas odd numbers are integers, whose last digit is 1, 3, 5, 7 or 9. Now we proceed to check the expression:
y = y + 8 Given
y + (- y) = 8 Compatibility with addition / Existence of additive inverse / Modulative property
0 = 8 Existence of additive inverse / Modulative property / Result
The expression y = y + 8 does neither represent an odd number nor an even number.
To learn more on even numbers: brainly.com/question/2289438
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Right triangle bc a^2+b^2=c^2. (Pythagorean theorem)
Answer:
The real solutions of f(x)=0 are: 0, 2, 5, 6
Step-by-step explanation:
We are given:
The graph of y = f(x)
We need to find all of the real solutions of f(x) = 0?
By looking at the graph we need to find the values of y when x =0
Looking at the graph, when x=0 we get
0, 2,5 and 6
So, the real solutions of f(x)=0 are: 0, 2, 5, 6
I am attaching the figure, that determines the answers.
B. It will have two zeros. Hope this helps!