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Salsk061 [2.6K]
3 years ago
7

Solve the equation x^13-2x^12-x^11+2x^10=0 in the real number system

Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0

Answer:

x= -1,  x=1  and x=2

Step-by-step explanation:

The equation is;

x^{13} -2x^{12} -x^{11} +2x^{10} =0

Using a graph tool to graph the equation and identify the solution you will have;

x= -1,

x=1

x=2

Check answers

when x=2

2^{13}-2(2^{12} )-2^{11} +2(2^{10} )\\\\\\2^{13} -2^1(2^{12} )-2^{11} +2^1(2^{10} )\\\\\\2^{13} -2^{13} -2^{11} +2^{11} =0

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Mr. Harrow has eight boys and six girls in his Honors Pre-calculus class. If he randomly chooses two students, one at a time, wh
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Answer: 15/91 which is choice B

=================================================================

There are two methods to find this answer.

Method 1) We have 6 girls and 8+6 = 14 students. The probability of picking a girl is 6/14 = 3/7. After the first girl is chosen, we have 5 girls left out of 14-1 = 13 students overall. The probability of picking another girl (assuming the first selection was a girl) is 5/13. Multiply these probabilities: (3/7)*(5/13) = (3*5)/(7*13) = 15/91

--------------------

Method 2) We can use the nCr combination formula. Order does not matter.

We have nCr = 6 C 2 = 15 ways to pick 2 girls. See the attached image below for the steps (figure 1)

Out of nCr = 14 C 2 = 91 ways to pick 2 students. See the attached image below for the steps (figure 2)

So that's another way to get the answer 15/91.

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