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2 years ago

Give an example of a compound inequality that has no solution

Mathematics

1 answer:

Vladimir79 [104]2 years ago

3 0

-3 < x < -8

There is no value of c that is greater than -3 AND less that -8

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Whats is a 3 step problem that can represent the expression 3x + (-5) = 19

GrogVix [38]

Answer:

$x=8$

Step-by-step explanation:

$3x-5=19\\$

The first step is to add -5 to both sides:

$(3x-5)+5=19+5\\3x=24$

The next step is to divide 3 on both sides:

$\frac{3x}{3} =\frac{24}{3}$

$x=8$

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2 years ago

2 ways to tell if there is a proportional relationship

Rus_ich [418]

Answer:

straight line and line goes through the origin.

Step-by-step explanation:

without a graph, you will need to divide y/x to seeing there is a constant rate or a constant number every time you divide.

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2 years ago

What’s 9n-3 simplified

Katarina [22]

Answer:

9n-3

Step-by-step explanation:

since 9n has a variable, u can't add or subtract 9n with 3

but if you were multiplying: 9n(3) then it would be 27n

7 0

2 years ago

HELP!!! THIS IS DUE AT 11:59!

Misha Larkins [42]

Answer:

1. x = 22

2. x = 38

3. x = 24

Step-by-step explanation:

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3 0

3 years ago

The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$

Hence, the quotient is (x-2).

6 0

3 years ago

Read 2 more answers