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Alenkinab [10]
3 years ago
13

What is the slope for (2, -1) and (3,1)

Mathematics
2 answers:
VMariaS [17]3 years ago
6 0

To find the slope (m), use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}        and plug in the two points

(2, -1) = (x₁, y₁)

(3, 1) = (x₂, y₂)

[lines usually go from left to right, so the point furthest to the left is the 1st point]

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{1-(-1)}{3-2}     [two negative signs cancel each other out and become positive]

m=\frac{1+1}{3-2}

m=\frac{2}{1}

m = 2

ale4655 [162]3 years ago
3 0

Answer: 2

Step-by-step explanation:

m = y2 - y1 /   x2- x1

where slope is m,

so in this case it would be

m= 1-(-1) / 3-2

m=2/1

m=2

Note that you can do it either way

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Read 2 more answers
PLEASE HELP WITH ALGEBRA AND SHOW WORK :) an explanation would be nice too because this topic confuses me :/
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A.

f(t) = t^2 + 4t-14\\ f(t)=t^2+4t+4-18\\ f(t)=(t+2)^2-18


B.

f(x)=(x-h)^2+k \Rightarrow \text{vertex}=(h,k)\\\\ f(t)=(t+2)^2-18 \Rightarrow \text{vertex}=(-2,-18)


It's a minimum, becuase a=1>0.


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